4 years ago

Simplify the exponents (2^2)2

2 answers:

Elena-2011 [213]4 years ago

3 0

Two to the 2nd power - to the 2nd power
so because you'd do 2•2 (the two exponents) then your answer would be 2^4 two to the 4th power

iogann1982 [59]4 years ago

3 0

It would be: (2²)2 = (4)2 = 8

so, your answer is 8

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What is the range of the function y = 4x + 3 for the domain 7 ≤ x ≤ 10?

Scrat [10]

Answer:

Step-by-step explanation:

Since y = 4x + 3 is a line, it is continuous over the whole real number system. In other words, there are no asymptotes or holes in it. If you want to determine the range for that function, simply plug the x-value of 7 into the function to solve for y at that x-value. If x = 7, then y = 4(7) + 3 and y = 31. When x = 10, then y = 4(10) + 3 and y = 43. That gives us the range

{y | 31 ≤ y ≤ 43}. That reads "y such that y is greater than or equal to 31 and less than or equal to 43."

7 0

3 years ago

Rename the fraction as a decimal.<br><br> 4/16=

aleksandrvk [35]

Answer:

0.25

Step-by-step explanation:

simplify 4/16 to 1/4.

multiply 1/4 by 25/25.

then you get 25/100, which equals to 0.25

3 0

3 years ago

(x^-2/y^-3)^2 / (y/x^2)^-3

Fiesta28 [93]

$\frac{ (\frac{ x^{-2} }{ y^{-3} })^2 }{ (\frac{y}{ x^{2} })^{-3} } = \frac{ (\frac{ x^{-4} }{ y^{-6} }) }{ (\frac{ y^{-3} }{ x^{-6} }) }= \frac{ x^{-4}* x^{-6} }{ y^{-3}* y^{-6} } = \frac{ x^{-10} }{ y^{-9} }$