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Romashka-Z-Leto [24]
4 years ago
15

Lily graphs segment LM. Then, she reflects the segment across the y-axis. Which statement compares the lengths of the egment LM

and its transformation overline LM correctly?
A)overline LM = overline LM overline
B)LM < overline LM
C)overline LM > overline LM
D)overline LM < overline LM
Mathematics
2 answers:
Andreas93 [3]4 years ago
8 0

Answer:

C

Step-by-step explanation:

dedylja [7]4 years ago
4 0
B ) Lm & lt; overland LM
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How to find the maximum or minimum value of a quadratic function?
kipiarov [429]

Answer:

Vertex form

Step-by-step explanation:

You convert to  vertex form  a(x - b)^2 + c . The coordinates of the maxm/minm will be (b, c).

For example find minimum value of  x^2 + 5x - 6:-

x^2 + 5x - 6

=  (x + 2.5)^2 - 6.25 - 6

= (x + 2.5)^2 - 12.25

The coordinates of minimumm will be (-2.5, -12.25)  The values of the minimum of the function is -12.25

6 0
4 years ago
A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a
Vesnalui [34]

Answer:

2.5

Step-by-step explanation:

A triangle ABC with vertices A(0, 0), B(0, 4), and C(6, 0) is dilated to form a triangle A'B'C' with vertices A′(0, 0), B′(0, 10), and C′(15, 0). If the center of dilation is point A or A' (the origin), then

\dfrac{A'B'}{AB}=\dfrac{A'C'}{AC}.

Since

  • AB=4;
  • A'B'=10;
  • AC=6;
  • A'C'=15,

then the scale factor of the dilation is

k=\dfrac{10}{4}=\dfrac{15}{6}=2.5.

3 0
3 years ago
9th grade Quizziz help please
jenyasd209 [6]

Answer:

a²+7a+10

a²+5a+2a+10

a(a+5)+2(a+5)

(a+5)(a+2)

a+2 is required factor

7 0
3 years ago
X+413=−256 <br> What is the value of X?
Phantasy [73]

Answer:

-669

Step-by-step explanation:

Convert -256 to 256

Addition -> 413+256=

669

Convert 669 to -669

X=-669

Double Check:

-669+413=-256

8 0
3 years ago
Use the graph below to fill in the blank with the correct number:
Alik [6]
Let
A(-3,0) \\ B(-2,2) \\ C(0,1) \\ D(1,-2)

we know that

Point A
A(-3,0) \\ for x=-3 \\ f(-3)=0

Point B
B(-2,2) \\ for x=-2 \\ f(-2)=2

Point C
C(0,1) \\ for x=0 \\ f(0)=1

Point D
D(1,-2) \\ for x=1 \\ f(1)=-2

therefore

the answer is
f(0)=1
4 0
3 years ago
Read 2 more answers
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