Question

Solve 4x to the second power Minus 9

Answer 1

2so 4x^2-9 is obviously the difference of 2 perfect squares

so (a)^2-(b)^2 can be factored into (a-b)(a+b)

so 4x^2-9=(2x)^2-(3)^2 which is (2x-3)(2x+3)

Answer 2

$4x^2-9$

Here I have included 3 methods: Differentiating, Integrating and factorize

Differentiating:

$4x^2-9$

$2*4x^2^-^1$

$8x^2^-^1$

$= 8x$

Integrating:

$\int\limits 4x^2-9dx$

$\frac{4x^3}{3}-9x+C$

Factorise:

$(2x-3)(2x+3)$