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Ira Lisetskai [31]
3 years ago
13

Question number 1: 5/8 (16b+24) -1/2b Question number 2: 3/4 (16/64 + 12a) -9a

Mathematics
1 answer:
Sophie [7]3 years ago
5 0

Answer:

Problem 1. <em>(19/2)b + 15</em>

Problem 2. <em>3/16</em>

Step-by-step explanation:

Question number 1

5/8 (16b+24) -1/2b  =

= (5/8) * (16/1) * b + (5/8) * 24 - (1/2)b

= 10b + 15 - (1/2)b

= (20/2)b - (1/2)b + 15

= (19/2)b + 15

Question number 2

3/4 (16/64 + 12a) -9a =

= (3/4) * (16/64) + (3/4) * 12a - 9a

= (3 * 16)(4 * 64) + (3/4) * (12/1) * a - 9a

= (3 * 1)(4 * 4) + (3 * 12)/(4 * 1) * a - 9a

= 3/16 + (3 * 3)/(1 * 1) * a - 9a

= 3/16 + 9a - 9a

= 3/16

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The sum of a number and its square is 182. Find the number.
Mars2501 [29]

Answer:

13 and -14 satisfy this condition

Step-by-step explanation:

Let's represent that number as x

and the square of x is x^2

So,

x + x^2 = 182

Subtract 182 from both sides

x + x^2 - 182 = 182 - 182

x + x^2 - 182 = 0

rearrange the quadratic equation

x^2 + x -182 = 0

let's use the quadratic formula

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a = 1, b = 1, c = -182

\frac{-1+\sqrt{1^2-4*1*(-182)} }{2*1}       or     \frac{-1-\sqrt{1^2-4*1*(-182)} }{2*1}

\frac{-1+\sqrt{1+728} }{2}      or         \frac{-1-\sqrt{1+728} }{2}

\frac{-1+\sqrt{729} }{2}            or    \frac{-1-\sqrt{729} }{2}

\frac{-1+{27} }{2}     or    \frac{-1-{27} }{2}

\frac{26}{2}     or    \frac{-28}{2}

13 or    - 14

Lets check

13 + 13^2 = 13 + 169

= 182

Also,

-14 + (-14^2) = -14 + 196

= 182

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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