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Ira Lisetskai [31]
2 years ago
13

Question number 1: 5/8 (16b+24) -1/2b Question number 2: 3/4 (16/64 + 12a) -9a

Mathematics
1 answer:
Sophie [7]2 years ago
5 0

Answer:

Problem 1. <em>(19/2)b + 15</em>

Problem 2. <em>3/16</em>

Step-by-step explanation:

Question number 1

5/8 (16b+24) -1/2b  =

= (5/8) * (16/1) * b + (5/8) * 24 - (1/2)b

= 10b + 15 - (1/2)b

= (20/2)b - (1/2)b + 15

= (19/2)b + 15

Question number 2

3/4 (16/64 + 12a) -9a =

= (3/4) * (16/64) + (3/4) * 12a - 9a

= (3 * 16)(4 * 64) + (3/4) * (12/1) * a - 9a

= (3 * 1)(4 * 4) + (3 * 12)/(4 * 1) * a - 9a

= 3/16 + (3 * 3)/(1 * 1) * a - 9a

= 3/16 + 9a - 9a

= 3/16

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stepladder [879]
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4 0
3 years ago
Why is x = 4 a solution to the proportion StartFraction 14 over x EndFraction = StartFraction 56 over 16 EndFraction?
mamaluj [8]

Answer:

D <u><em>Because if you substitute 4 into the equation for x and cross multiply, you get 224 = 224.</em></u>

Step-by-step explanation:

When you cross multiply, you get 14×16=224, and 224÷4=56.

6 0
3 years ago
Read 2 more answers
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

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2 years ago
A cross country racer records a time of exactly 4 minutes to complete a race that is a distance of 1,000 meters. What is the rac
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Answer:

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Step-by-step explanation:

6 0
2 years ago
THANKS FOR ANSWERING <br> ✔✔
Fantom [35]

Answer:

-14 1/2, -14, 10/20, 0.6

7 0
2 years ago
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