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2 years ago

Given the equation of a line: 6x-3y+8=0,

Mathematics

2 answers:

makkiz [27]2 years ago

6 0

Answer:

y = 2x + 8/3

Step-by-step explanation:

slope y-intercept form => y = mx + b

=> -3y = -6x - 8

=> y = 2x + 8/3

marysya [2.9K]2 years ago

3 0

Answer: y = 2x + 8/3

Step-by-step explanation:

6x - 3y +8 = 0

-3y + 8 = -6x

-3y = -6x - 8

y = 2x + 8/3

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Can someone help me convert each of these into improper fractions?

mariarad [96]

Answer:

$(\frac{6}{1})(\frac{11}{4} )$

$(-\frac{10}{3})(-\frac{17}{5})$

$(-\frac{9}{2} )(\frac{26}{3} )$

$(\frac{11}{6})(-\frac{9}{1} )$

Step-by-step explanation:

I hope this help you

8 0

2 years ago

Differentiating Exponential functions In Exercise,find the derivative of the function. See Example 2 and 3.

nadya68 [22]

Answer:

f'(x) $=2(e^4^x)+(x^2+1)(4e^4^x)$

Step-by-step explanation:

The derivative of the function:

$(x^2+1)e^4^x$

The rule for the product of two functions:

f'(x) $=g'(x)h(x)+g(x)h'(x)$

Therefore

g(x) $=x^2+1$

g'(x) $=2$

f(x) $=e^4^x$

f'(x) $=4e^4^x$

f'(x) $=2(e^4^x)+(x^2+1)(4e^4^x)$

4 0

3 years ago

Which integer represents this situation?

Vinil7 [7]

The Answer of the question is "B" or 1,600

6 0

3 years ago

James had a business mowing lawns for $25 per lawn and raking leaves for $0.75 per pile. His goal is to earn exactly $37 each ti

Marizza181 [45]

Answer:

Step-by-step explanation:

3 0

2 years ago

Greta is trying to determine the portion of green candies in various bags of green and yellow candies. Using the information bel

IrinaK [193]

Answer: a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

Step-by-step explanation:

Since we have given that

There are green and yellow candies in each bag.

Bag A: Two thirds of the candies are yellow. What portion of the candies is green?

Part of yellow candies in bag A = $\dfrac{2}{3}$

Part of green candies in bag A would be

$1-\dfrac{2}{3}\\\\=\dfrac{3-2}{3}\\\\=\dfrac{1}{3}$

Bag B: 29 % of the candies are yellow. What portion of the candies is green?

Percentage of candies are yellow = 29%

Portion of candies are green is given by

$1-\dfrac{29}{100}\\\\=1-0.29\\\\=0.71\\\\=\dfrac{71}{100}$

Bag C: 4 out of every 9 candies are yellow. What portion of the candies is green?

Portion of yellow candies = $\dfrac{4}{9}$

Portion of green candies would be

$1-\dfrac{4}{9}\\\\=\dfrac{9-4}{9}\\\\=\dfrac{5}{9}$

Hence, a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

6 0

2 years ago