
- a number

- its square

- the sum

- less than or equal
negative three - I don't have to explain this one, do I?

- the sum of a number and its square is less than or equal negative three
One
RemarkThis is very complicate unless you pick the right method. It's very handy o know about substitutions.
MethodLet z = (k + 2)^2
Now the problem becomes
z + 16/z = 92 Multiply through by z
Solutionz^2 + 16 = 92z
That does not look very promising. If you know the quadratic formula, this mess can be solved. If you do not know what the quadratic formula is, then what I've written is the answer.
Worse yet, you have to know what complex numbers are. Is this something you know about? The z form of this equation is fine. It gives answers that are rational. The problem is that both are negative and so in your next step, you will be forced to take the square root of a negative number.
Maybe the answer is just
(x + 3)^ + 16 = 92(x + 3)^2
If all you have to do is expand this then you get
x^2 + 6x + 9 + 16 = 92(x^2 + 6x + 9) Remove the brackets.
x^2 + 6x + 25 = 92x^2 + 552x + 828 Put the left over to the right.
0 = 92x^2 - x^2 + 552x - 6x + 828 - 25
0 = 91x^1 + 546x + 803
It looks that way from the second question. If I'm wrong about that, put a comment down below.
Two Put over a common denominator and expand
Answer:
-3x - 7 is the furthest it can be simplified
1a. 21/3+32/5
((2*3)+1)/3+((3*5)+2)/5
7/3+17/5
(7*5+17*3)/15
86/15
1b. 2/3+3/5+2/5
(2*5+3*3+2*3)/15
(10+9+6)/15
25/15
5/3
2a. 57/10-22/5
(5*10+7)/10-(2*5+2)/5
57/10-12/5
(57*1-2*12)/10
33/10
2b. 5/12-1/4
(5*1-1*3)/12
2/12
1/6
3 say she has x stamps,she gave 2/9 and 1/5 to her frends so she is left with
X-2x/9-x/5
(9*5x-5*2x-9*1x)/45
(45x-10x-9x)/45
26x/45
4. 7/10+1/5
(1*7+2*1)/10
9/10
5. Brick 21/3kg
Stone (2*3+1)/3-(1*10+1)/10
7/3-11/10
(7*10-3*11)/30
(70-33)/30
37/30
Answer:
y=-5x+12
Step-by-step explanation: