$9147 x 12 =190,764
12 is how many months there is in a year
Answer:

Step-by-step explanation:
We have to vertically stretch the function
by a factor of 2.
Then the function will become
.
Then it is reflected across the x-axis.
So, the new function will be
.
Now, if the function is shifted down 3 units then the final function will become
(Answer)
Answer:
see the attachment
Step-by-step explanation:
We assume that the question is interested in the probability that a randomly chosen class is a Friday class with a lab experiment (2/15). That is somewhat different from the probability that a lab experiment is conducted on a Friday (2/3).
Based on our assumption, we want to create a simulation that includes a 1/5 chance of the day being a Friday, along with a 2/3 chance that the class has a lab experiment on whatever day it is.
That simulation can consist of choosing 1 of 5 differently-colored marbles, and rolling a 6-sided die with 2/3 of the numbers being designated as representing a lab-experiment day. (The marble must be replaced and the marbles stirred for the next trial.) For our purpose, we can designate the yellow marble as "Friday", and numbers greater than 2 as "lab-experiment".
The simulation of 70 different choices of a random class is shown in the attachment.
_____
<em>Comment on the question</em>
IMO, the use of <em>70 trials</em> is coincidentally the same number as the first <em>70 days</em> of school. The calendar is deterministic, so there will be exactly 14 Fridays in that period. If, in 70 draws, you get 16 yellow marbles, you cannot say, "the probability of a Friday is 16/70." You need to be very careful to properly state the question you're trying to answer.
Answer:
\[y = (-1/2) * x + 6\]
Step-by-step explanation:
Equation of the given line: y=2x+2
Hence the slope of the line is given by 2
Any line which is perpendicular to the given line will have a slope m such that m*2 = -1
Or, \[m = \frac{-1}{2}\]
Only options 2 and 3 satisfy this condition.
The line is also supposed to pass through the point (6,3).
Substituting these values in the option 2:
\[3 = (-1/2) * 6 + 3\]
Or, \[ 3 =0 \] which is false . Hence option 2 is not valid.
Now substituting (6,3) in option 3:
\[3 = (-1/2) * 6 + 6\]
Or, \[ 3 =3 \] which is true . Hence option 3 is the required equation of the line.