The answer is true. It does increase
1. 8p-3=13
+3
8p=16 /8
p=2
2. 8j -5 +j=67
== 9j=72 /9
j=8
3. 3(2x-5)=4x+33 <--- =expand ()
6x-15=4x+33 ---> 2x=48
x=24
4. c=b-bx
get just x's on one side
c-b=bx
divide by b---> (c-b)/b=x
Answer: (a−c)(b−c)>0
Step-by-step explanation:
ab>1 and ac<01. a>0 if c<0 and also b>02. a<0 if c>0 and also b<0
how i did it:
At the vert first, write the inequality as an equation.
Solve the provided equation for one or more values.
Now, display all the values obtained in the number line.
Use open circles to show the excluded values on the number line.
Find the interim.
At the moment, take any random value from the interval and substitute it in the inequality equation to check whether the values reassure the inequality equation.
Intervals that reassure the inequality equation are the solutions of the given inequality equation.
Answer:
"A value that is substituted in for the variable in a function in order to generate an output value" is gonna be known as an input.
"A group of two numbers written in the form (x, y) where the x value represents a horizontal position and the y value represents a vertical position" is known as an ordered pair.
"A value generated by a function when an input value is substituted into the function and evaluated" is known as an output.
I hope I have helped with this problem. Have a good day.
