So x times y=3030
x and y=unknown
find the factors (factors of 6=2 and 3)
3030=2,3,5,101 so
two multiplication is
2 times 1515
3 times 1010
5 times 606
30 times 101
202 times 15
303 times 10
505 times 6
<h3>
Answer: -20</h3>
==========================================================
Work Shown:
Let x be the location of E on the number line.
Since C is the midpoint of E and F, this means we can find C's location by adding E and F together and dividing that sum by 2
midpoint = (endpoint1 + endpoint2)/2
C = (E+F)/2
Plug in E = x, C = -8 and F = 4. Then solve for x
C = (E+F)/2
-8 = (x+4)/2
(x+4)/2 = -8
x+4 = 2(-8) .... multiplying both sides by 2
x+4 = -16
x = -16-4 .... subtract 4 from both sides
x = -20
The location of point E on the number line is -20
-------------
As a check, lets add E and F to get E+F = -20+4 = -16
Then cut this in half to get -16/2 = -8, which is the proper location of point C
This confirms our answer.
Answer:
The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>
Step-by-step explanation:
Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.
We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

Since, given the difference of the squares of the numbers is 5 that is 
And the product of the numbers is 6 that is 
Using identity, we have,

Substitute, we have,

Simplify, we have,


Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169
Answer:
249.4
Bc if you do 89,790 divided by 365 your answer should be 249.4 and some more numbers
C it is c ajdbdiwdidnwisnxidnend