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katrin [286]
3 years ago
5

Item 1 5 units Cost $50 Market $45 Item 2 7 units Cost $60 Market $65 Item 3 9 units Cost $30 Market $25 Applying the lower of c

ost or market method, the reported value of this company's ending inventory if LCM is applied to individual items is _____. $870 $905 $920 $940
Business
1 answer:
Alexeev081 [22]3 years ago
7 0

Answer:

The answer is A. $870

Explanation:

The lower-of-cost-or-market (LCM) method measures closing or ending inventory at the lower of its cost(historical cost) or its current market cost(replacement cost). This situation arises when inventory has deteriorated, or has become obsolete, or market prices have gone down.

Item 1...... 5 units x $45 = $225

Item 2..... 7 units x $60 = $420

Item 3..... 9 units x $25 = $225

Total......................................$870

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The amount of money you can charge to a credit card is called
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In response to threats from such companies as Amazon, established manufacturers and retailers became "brick-and-click" oriented
docker41 [41]

Answer:

Re-intermediation

Explanation:

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6 0
3 years ago
The cob Douglas production function is given by Q(K,L)=AK^1.4*L^1.6
Alexeev081 [22]

Part a) The Cob Douglas production function is given as:

Q(K,L)=AK^{1.4} L^ {1.6 } .

To show that this function is homogeneous with degree 3, we introduce be a parameter, t.

Q(tK,tL)=A(tK)^{1.4} (tL)^ {1.6 } .

Using properties of exponents, we on tinder:

Q(tK,tL)=At^{1.4}K^{1.4} t^ {1.6 }L^ {1.6 } .

This implies that:

Q(tK,tL)=t^{1.4} \times t^ {1.6 }(AK^{1.4} L^ {1.6 } )

Q(tK,tL)=t^{1.4 + 1.6}(AK^{1.4} L^ {1.6 } )

Simplify the exponent of t to get;

Q(tK,tL)=t^{3}(AK^{1.4} L^ {1.6 } )

Hence the function is homogeneous with degree, 3

Part b) To verify Euler's Theorem, we must show that:

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L}=3AK^{1.4}L^{1.6}

Verifying from the left:

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =K(1.4AK^{0.4} L^{1.6}) + L(1.6AK^{1.4} L^{0.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =1.4(AK^{1.4} L^{1.6}) + 1.6(AK^{1.4} L^{1.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =(1.4 +  1.6)(AK^{1.4} L^{1.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =3(AK^{1.4} L^{1.6})

Q•E•D

8 0
3 years ago
The Casings Plant of Wyoming Machines makes plastics shells for the company’s calculators. (Each calculator requires one shell.)
aniked [119]

Answer and Explanation:

a. The computation of the targeted production of the finished product is shown below:

= Expected sales units - beginning finished goods + ending finished goods

= 160,000 - 20,000 + 5,000

= 145,000 shells

b. The required amount of plastic purchased is

Plastic to be purchased = Consumed plastic + closing inventory - opening inventory

where,

Consumed plastic is

= 145,000 × 6 ounces

= 870,000 ounces

Opening inventory is 60,000  ounces

And, the closing inventory is

= 160,000  ÷ 12 months × 2 months × 6 ounces

= 160,000

So, the purchased plastic is

= 870,000 + 160,000 - 60000

= 970,000 ounces

5 0
4 years ago
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