1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Crank
3 years ago
7

Consider the function below. f(x) = ln(x4 + 27) (a) Find the interval of increase. (Enter your answer using interval notation.)

Find the interval of decrease. (Enter your answer using interval notation.) (b) Find the local minimum value(s). (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) Find the local maximum value(s). (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) (c) Find the inflection points. (x, y) = (smaller x-value) (x, y) = (larger x-value) Find the interval where the graph is concave upward. (Enter your answer using interval notation.) Find the intervals where the graph is concave downward. (Enter your answer using interval notation.)
Mathematics
1 answer:
andrezito [222]3 years ago
6 0

Answer:

a) The function is constantly increasing and is never decreasing

b) There is no local maximum or local minimum.

Step-by-step explanation:

To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.

f(x) = ln(x^4 + 27)

f'(x) = 1/(x^2 + 27)

Now we take the derivative and solve for zero to find the local max and mins.

f'(x) = 1/(x^2 + 27)

0 = 1/(x^2 + 27)

Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.

You might be interested in
Prove that these two triangles are congruent.
fredd [130]

Answer:

thank for the pointshhhhfgtf5ttctctx4dd5y8hhousjshs

6 0
3 years ago
I need help please and thank u,
Alchen [17]

The illegal values of b are when the denominator equals 0.

So, b^2-2b-8=0 gives you (b-4)(b+2)=0

Therefore, b=4 and b=-2, which is answer A.


8 0
3 years ago
Need help asap!!! (will give BRAINLEIST)
madam [21]

Answer:

false

Step-by-step explanation:

rainbow method or tabular method x^2+4x+4

7 0
3 years ago
Read 2 more answers
7700÷623 with answer and remainder
Free_Kalibri [48]
7700/623
= 623*12 + 224

Therefore, the answer is 12 and the remainder is 224.

Hope this helps !

Photon
3 0
3 years ago
Read 2 more answers
Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen
Jobisdone [24]

Parameterize S by the vector function

\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k

so that the normal vector to S is given by

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k

with magnitude

\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}

In this case, the normal vector is

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k

with magnitude \sqrt{1^2+2^2+1^2}=\sqrt6. The integral of f(x,y,z)=e^z over S is then

\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx

where T is the region in the x,y plane over which S is defined. In this case, it's the triangle in the plane z=0 which we can capture with 0\le x\le8 and 0\le y\le\frac{8-x}2, so that we have

\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}

5 0
3 years ago
Other questions:
  • Three other samples were taken using the same confidence
    10·1 answer
  • At one time will the hour and minute hand of a clock form a 105 degree angle?
    13·2 answers
  • Alison can pay for her gym membership on a monthly basis but if she pays for an entire year of the membership and event shall re
    5·1 answer
  • The average demand for rental skis on winter Saturdays at a particular area is 150 pairs, which has been quite stable over time.
    13·1 answer
  • What are chemical bands​
    11·1 answer
  • Triangle ABC has the following angle measurements
    8·2 answers
  • A cup contains seven red erasers, four
    12·1 answer
  • Write the equation of the line in fully simplified slope-intercept form
    15·1 answer
  • 1/2+3/4 1/2+3/4=2/4+3/4=5/4 or 11/4
    13·1 answer
  • What is the range? 6 7 8 7 10​
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!