About 4:39.
Hope this helps~!
~{Isle of flightless birds}
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
7x + 18 > -3
Subtract 18 from both sides,
7x > -21
Divide from 7,
x > -3
In short, Your Answer would be Option D
Hope this helps!
Answer:
what the h3ll type of question is this ?-
Step-by-step explanation:
your never gonna get one because you dont have any so the probability is 0%.
X would equal 60 degrees because the degree of the top left area is equal to the degree of the bottom right. So the equation would be x+20=80 so you would solve to get x=60
