In the linear equation y = 4x + 2, the value 2 represents which of the following?

PLEASEE HELPP Analyze these two graphs, which show the population growth (per thousands of people) of North Carolina and the Uni

Tju [1.3M]

I believe it’s A because if you notice the rate of population grow was in the 20,000s for the US in the 1840s, while NC was hitting 600 free people at that time.

5 0

3 years ago

The moon appears red during a lunar eclipse because red is the __________ wavelength of light in the color spectrum present in s

Sav [38]

Answer:

Longest

Step-by-step explanation:

The moon appears red during a lunar eclipse because red is the Longest wavelength of light in the color spectrum present in sunlight.

-Please Mark As Brainliest

8 0

3 years ago

Please help me with this and thank you

Over [174]

Answer:

The answer is D

Step-by-step explanation:

(12 + 6) x (11 - 7) = 72

18 x 4 = 72

72 = 72

The answer is D

7 0

3 years ago

Will give brainliest

Sonja [21]

The sum of the two rational equations is equal to (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²).

<h3>How to simplify the addition between two rational equations</h3>

In this question we must use algebra definitions and theorems to simplify the addition of two rational equations into a single rational equation. Now we proceed to show the procedure of solution in detail:

(n + 5) / (n² + 3 · n - 10) + 5 / (3 · n²) Given
(n + 5) / [(n + 5) · (n - 2)] + 5 / (3 · n²) x² - (r₁ + r₂) · x + r₁ · r₂ = (x - r₁) · (x - r₂)
1 / (n - 2) + 5 / (3 · n²) Associative and modulative property / Existence of the multiplicative inverse
[3 · n² + 5 · (n - 2)] / [3 · n² · (n - 2)] Addition of fractions with different denominator
(3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²) Distributive property / Power properties / Result

To learn more on rational equations: brainly.com/question/20850120

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4 0

2 years ago

Construc t a 95% confidence interval for the population standard deviation σ of a random sample of 15 men who have a mean weight

GrogVix [38]

The 95% confidence interval for the population standard deviation will be,

$$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\$

simplifying the equation, we get

$$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288$

The 95% confidence interval exists (9.887, 21.288).

<h3>What is the 95% of confidence interval?</h3>

A random sample of 15 men exists selected. The mean weight exists at $165.2 pounds and the standard deviation exists at $13.5 pounds. The population exists normally distributed.

So, $n=15, \bar{X}=165.2, s=13.5$

where n exists the sample size, $\bar{X}$ exists the sample size

s exists the sample standard deviation.

The degrees of freedom will be n - 1 i.e.15 - 1 = 14.

For a 95% confidence interval, the level of significance will be $\alpha=0.05$ .

The 95% confidence interval for the population standard deviation will be,

$$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\$

substitute the values in the above equation, we get

$$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi^{2}} 0.05} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0}^{2}}} \\$

$$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.975}^{2}}} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.025}^{2}}} \\$

simplifying the above equation, we get

$$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288$

The 95% confidence interval exists (9.887, 21.288).

To learn more about confidence interval refer to:

brainly.com/question/14825274

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6 0

2 years ago