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ahrayia [7]
3 years ago
14

Aleta’s puppy gained 3/8 pound each week for 4weeks . Although, how much weight did the puppy gain during 4 weeks

Mathematics
1 answer:
patriot [66]3 years ago
6 0
For the first one you have to do 3/8 times 4 and you will get 12/8 which you have to simplify and you’ll get 1 4/8 which simplify again to 1 1/2 and the answer is 1 1/2
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klio [65]

Answer:

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Step-by-step explanation:

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Inessa05 [86]

Answer:

D.) If soccer balls are sold for $2.05 or $14.61 each, the store will break even but will not make a profit.

Step-by-step explanation:

Let us assume x = selling price of each soccer ball

y = daily profit earned from selling of soccer balls

Given that

Y= -6x^2+100x-180

where,

a = -6

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c = -180

Now we have to applied the formula which is as follows

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

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= \frac{- 175.3658}{-12}

x^2 = 14.6138

Based on this the option D is most appropriate as per the given situation

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2 years ago
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ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)
Delicious77 [7]
remember
ln(x)=log_e(x)
and
log_x(a)-log_x(b)= log_x( \frac{a}{b} )
and
log_a(b)=c means a^c=b
and
blog(a)=log(a^b)



so

ln(y+1)-ln(y)=1+3ln(x)
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minus ln(x^3) from both sides

ln( \frac{y+1}{y}-ln(x^3) )=1
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translate

e^1=\frac{y+1}{yx^3}
e=\frac{y+1}{yx^3}

times both sides by yx^3

eyx^3=y+1

minus y from both sides

eyx^3-y=1
y(ex^3-1)=1

divide both sides by (ex³-1)

y= \frac{1}{ex^3-1}
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3 years ago
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To increase an amount by 3% what single multiplier would you use?<br> thanks :)
KATRIN_1 [288]
X - an amount

x+3\%x=x+0.03x=1.03x

To increase an amount by 3% you can multiply the amount by 1.03.
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