All categories

3 years ago

What is 4 (m + n) -5 (m - n) ?

Mathematics

1 answer:

Galina-37 [17]3 years ago

5 0

Answer:

Step-by-step explanation:

for this situation we do distributive property{in distributive property [in this situation ] we will (multiply 4 by m & n) - (multiply 5 by m & n)=

4m + 4n - 5m - 5n =

(4m -5m) - (4n - 5n) =

-1m - (- 1n) =

-1m + 1n

and always remember to go in alphabetical order = m comes before n, x comes before y or z.

You might be interested in

Whats the square root of '0'? What is it?

Aneli [31]

The square root of zero is zero. Because 0 * 0 = 0.

8 0

3 years ago

4 1/3 · 3/5 express your answer in simplest form. A. 2 3/5 B. 2 C. 4 1/5 D. 1 1/15

a_sh-v [17]

Oh the answer is a I looked it up this time

7 0

3 years ago

Read 2 more answers

2p^2+2p-4 solve using the AC method or the sum product method .. PLEASE HELP thank you :)))

Leviafan [203]

Answer: 2(p+2) * (p-1)

Step-by-step explanation:

2p^2 + 2p - 4

2 (p^2 + p - 2)

2 (p^2 + 2p - p - 2)

2(p x (p+2) - (p+2)

2 (p+2) * (p-1)

3 0

3 years ago

Please answer i have finals this coming week and i need to get my grade up

sveticcg [70]

Answer:

first line for you graph would be from 5 to 5 and the second line is -4 to 2

Step-by-step explanation:

hope this is what you needed:)

4 0

2 years ago

How did the transformation of ()=f of , open x close . equals , x squared to ()=−g of , open x close . equals , x squared , minu

Nikolay [14]

The intercepts are the points where the graph crosses the x or y-axis

The x-intercepts changed from 0 to $\±\sqrt 3$ .
The y-intercepts changed from 0 to 3

The functions are given as:

$f(x) = x^2$

$g(x) = x^2 - 3$

Function f(x)

$f(x) = x^2$

The x-intercept is calculated as follows:

Set f(x) to 0

$x^2 = 0$

Solve for x

$x = 0$

The y-intercept is calculated as follows:

Set x to 0

$f(0) = 0^2$

$f(0) = 0$

Hence, the intercepts are 0

Function g(x)

$g(x) = x^2 - 3$

The x-intercept is calculated as follows:

Set g(x) to 0

$x^2 - 3 = 0$

Solve for x

$x^2 = 3$

$x = \±\sqrt 3$

The y-intercept is calculated as follows:

Set x to 0

$g(x) = x^2 - 3$

$g(0) = 0^2 - 3$

$g(0) = - 3$

The x-intercepts are $\±\sqrt 3$ , while the y-intercept is -3

By comparing the intercepts of f(x) and g(x),

The x-intercepts changed from 0 to $\±\sqrt 3$ .
The y-intercepts changed from 0 to 3