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3 years ago

help? I know what i’m doing somewhat but i really just didn’t wanna pay attention in class the day this was taught

Mathematics

2 answers:

PIT_PIT [208]3 years ago

7 0

To solve the equation for x, first divide both sides of the equation by 4 to get $e^{2.7x}=\frac{33}{4}$ . Then, take the natural logarithm of both sides (base e) to get $\ln e^{2.7x} = \ln (33/4)$ . The left hand side of this equation if equal to 2.7x, so we get $2.7x = \ln(33/4)$ . The final step is to divide both sides of the equation by 2.7, to get that $x =\frac{ \ln (33/4)}{2.7}$ . This is approximately equal to 0.782.

Komok [63]3 years ago

4 0

Answer:

ily

Step-by-step explanation:

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No one has answered this one

krek1111 [17]

Answer:

$\displaystyle x = \frac{25\sqrt{2}}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] cosθ = adjacent over hypotenuse

Step-by-step explanation:

Step 1: Define

Identify variables

Angle θ = 45°

Adjacent Leg = 25

Hypotenuse = x

Step 2: Solve for x

Substitute in variables [cosine]: $\displaystyle cos(45^\circ) = \frac{x}{25}$
[Multiplication Property of Equality] Multiply 25 on both sides: $\displaystyle 25cos(45^\circ) = x$
Rewrite: $\displaystyle x = 25cos(45^\circ)$
Evaluate: $\displaystyle x = \frac{25\sqrt{2}}{2}$

7 0

3 years ago

Assume that y is directly proportional to x. Use the given x-value and y-value to find a linear model that relates y and x.

steposvetlana [31]

Answer:

Step-by-step explanation:

To find a linear model, you need to use the formula y = kx and solve that for k. k is the constant of variation, also known as the slope of a line. Hence, the word "linear".

If y = kx and y = 1010 and x = 5, then

1010 = 5k so

k = 202

The linear model, then, is

y = 202x

3 0

3 years ago

Algebra 1 Prerequisites

frozen [14]

No solution

explanation:

5 0

3 years ago