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Elan Coil [88]
3 years ago
6

In Triangle ABC, which trigonometric ratio has the value a/c?

Mathematics
2 answers:
jekas [21]3 years ago
8 0

The answer is A) tan A.

jeka943 years ago
7 0
B cos A hope this helps
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John is a quarterback. This year, he completed 350350350 passes, which is 70\%70%70, percent of all the passes he's attempted th
-Dominant- [34]

let 'x' represent the number of all the passes for the year

350 passes = 70% of all the passes

350 passes = 70% of x

0.70x = 350

by solving we find:

x = 500 passes

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3 years ago
How to factor 3x^2-10x-8?
Soloha48 [4]

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3 years ago
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Identify the zeros of the function f(x) = 2x^2 − 4x + 5 using the Quadratic Formula
Nostrana [21]

For this case we have that by definition, the roots, or also called zeros, of the quadratic function are those values of x for which the expression is 0.

Then, we must find the roots of:

2x ^ 2-4x + 5 = 0

Where:

a = 2\\b = -4\\c = 5

We have to:x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

Substituting we have:

x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (2) (5)}} {2 (2)}\\x = \frac {4 \pm \sqrt {16-40}} {4}\\x = \frac {4 \pm \sqrt {-24}} {4}

By definition we have to:

i ^ 2 = -1

So:

x = \frac {4 \pm \sqrt {24i ^ 2}} {4}\\x = \frac {4 \pm i \sqrt {24}} {4}\\x = \frac {4 \pm i \sqrt {2 ^ 2 * 6}} {4}\\x = \frac {4 \pm 2i \sqrt {6}} {4}\\x = \frac {2 \pm i \sqrt {6}} {2}

Thus, we have two roots:

x_ {1} = \frac {2 + i \sqrt {6}} {2}\\x_ {2} = \frac {2-i \sqrt {6}} {2}

Answer:

x_ {1} = \frac {2 + i \sqrt {6}} {2}\\x_ {2} = \frac {2-i \sqrt {6}} {2}

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3 years ago
Find the value of x. Just type in the number​
Irina18 [472]

Answer:66

Step-by-step explanation:

8 0
2 years ago
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Alexus [3.1K]
3 because the next number to the right is a 0 and will not be rounded up.
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