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Stella [2.4K]
3 years ago
14

The profit P (in thousands of dollars) for an educational publisher can be modeled by P 52b31 5b21b where b is the number of wor

kbooks printed (in thousands). Currently, the publisher prints 5000 workbooks and makes a profit of $5000. What lesser number of workbooks could the publisher print and still yield the same profit?

Mathematics
1 answer:
Anna007 [38]3 years ago
7 0

Answer:

The lesser number of workbooks are 1,000

Step-by-step explanation:

The correct question is

The profit P (in thousands of dollars) for an educational publisher can be modeled by P=-b³+5b²+b where b is the number of workbooks printed (in thousands). Currently, the publisher prints 5000 workbooks and makes a profit of $5000. What lesser number of workbooks could the publisher print and still yield the same profit?

we have

P=-b^3+5b^2+b  

For P=\$5,000

substitute in the equation and solve for b

Remember that the profit and the number of workbooks is in thousands

so

P=5

5=-b^3+5b^2+b

Using a graphing tool

Solve the cubic function

The solutions are

x=-1

x=1

x=5

therefore

The lesser number of workbooks are 1,000

<u><em>Verify</em></u>

For b=1

P=-(1)^3+5(1)^2+1  

P=5  -----> is in thousands

so

P=\$5,000 ----> is ok

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Answer:

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Step-by-step explanation:

Multiply the numbers:

<u>4</u>X^2 y^3 x <u>2</u>x^3 y^4

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Combine Exponents:

8<u>^2</u> ^3 <u>^3</u> ^4

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7 0
2 years ago
1.Given the function h(t) = t³ - 2t, find h(-5).​
Svetllana [295]

Answer:

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Step-by-step explanation:

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7 0
2 years ago
List the next four multiples of fraction 7/12
Sidana [21]
<h2>Hello!</h2>

The answer is:

\frac{14}{12}=\frac{7}{12}*2\\\\\\\frac{21}{12}=\frac{7}{12}*3\\\\\\\\\frac{28}{12}=\frac{7}{12}*4\\\\\\\\\frac{35}{12}=\frac{7}{12}*5

<h2>Why?</h2>

A multiple of a number is the repeated sum of itself, for example:

Multiple of the number 1 are: 1, 2, 3, 4, 5 and so...

Multiple of the number 3 are: 3, 6, 9, 12, 15 and so...

From the example we have:

Multiple of the number 3 are: Itself, (3+3), (3+3+3), (3+3+3+3), (3+3+3+3+3) and so...

So,

Multiple of \frac{7}{12} are:

\frac{14}{12}=\frac{7}{12}*2=\frac{7}{12}+\frac{7}{12}\\\\\\\frac{21}{12}=\frac{7}{12}*3=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{28}{12}=\frac{7}{12}*4=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{35}{12}=\frac{7}{12}*5=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}

Have a nice day!

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3 years ago
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Answer:

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Step-by-step explanation:

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