Question

Line k contains the points (-4,0) and (3,2). line m contains the points (-3,2) and (4,0). if line k is written in the form y=m1x+b1 and line m is written in the form y=m2x+b2, what is the value of m1b2+m2b1?
what are the steps for solving this please?

Answer 1

Answer:

0

Step-by-step explanation:

(-4,0) and (3,2)

m1=(2-0)/(3+4)=2/7

y=2/7x+b1, using point (-4,0) to find b1 (substitute x=-4 and y=0 in the form)

0=2/7*(-4)+b1 ⇒ b1= 8/7

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(-3,2) and (4,0)

m2=(0-2)/(4+3)= -2/7

y= -2/7x+b2, using point (4,0) to find b2 (substitute x=4 and y=0 in the form)

0= -2/7*4+b2 ⇒ b2=8/7

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m1b2+m2b1= 2/7*8/7 -2/7*8/7=0