Answer:
% Po lost = 100[1 - e^(-0.005t)] %; 73.0 g
Step-by-step explanation:
p(t) = 100e^(-0.005t)
Initial amount: p(0) = 100
Amount remaining: p(t) = 100e^(-0.005t)
Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]
% of Po lost = amount lost/initial amount × 100 %
= [1 - e^(-0.005t)] × 100 % = 100[1 - e^(-0.005t)] %
p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g
The mass of polonium remaining after 63 days is 73 g.
Answer:
50cm
200cm
50cm^2
Step-by-step explanation:
The big square is divided into 4 with a side length of 25cm. 2 small square side lengths make up the big squares.
25 * 2 =
50cm
50 + 50 + 50 +50 =
200
15 +2
17
8 + 2
10
17 * 10 = 170
15 * 8 = 120
170-120 = 50
50cm^2
The percent for a male is 68.75 %
110+50=160 160=100%
Females:
100% is 160
What percent is 50?
160x=50x100
160x=5000
x=5000/160
x=31.25 Females =31.25% Males 100%-31.25%= 68.75%
Answer:
In inches, the radius of the can is <u>2</u>.
Step-by-step explanation:
Given:
The number of cubic inches in the volume of a 6-inch high cylindrical can equals the number of square inches in the area of the label that covers the lateral surface of the can.
Now, to find the radius of the can in inches.
Let the radius of can be 
Height of can = 
<em>As given, the number of cubic inches of the volume of the cylindrical can equals the number of square inches in the area of the label that covers the lateral surface of the can.</em>
<em><u>So, </u></em>
<em><u>Volume of can = lateral surface area of can.</u></em>
Now, we put formula of volume and lateral surface area of cylinder:
<em>Dividing both sides by </em>
<em> we get:</em>
<em />
<em />
<em />
<em />
<em>Dividing both sides by 6 we get:</em>
Therefore, in inches, the radius of the can is <u>2</u>.
Answer:
5. Not sure
6. Its linear since the first difference is constant.
7. Linear since its a line.
8. Slope/Rate of Change/M = Rise over Run = rise/run.
From the left point to the right, the rise is 3 and run is 10.
M = 3/10.
Hope this helped
Step-by-step explanation:
