FALSE it will not because there are two points with the same X value
The zeroes of the equation are (1,4)
Step-by-step explanation:
Given equation is:

We have to put y=0 in the equation to find zeroes of the equation

Hence,
The zeroes of the equation are (1,4)
Keywords: Equation, zeroes of an equation
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Answer:
(15,16)
Step-by-step explanation:
C=halfway between A to B
A to B on the x axis goes across by 24
24/2 =12
3+12=15
A to B on the y axis goes up by 28
28/2 = 14
2+14=16
(15,16)
2t-2=26
first you would add 2 to both sides
that equals 2t=28
then you would divide both sides by two
that would give you
t= 14