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Nataly [62]
3 years ago
10

Helpppppppppppppppppppp

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
5 0
Dude stop commenting that people need real answer not a link
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Step-by-step explanation:

All real numbers because x can assume every possible value

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What does noncollinear
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Answer:

  not on the same line

Step-by-step explanation:

Any two distinct points define a line. Additional points may or may not be on that line. If they are on the line, they are collinear with other points on the same line.

Any point not on the line is noncollinear with the points that are on the line.

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I need some help i cant figure this out
Luden [163]

Answer:

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Step-by-step explanation:

at least on my end it is.

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18) the answer is 3 because CD is a segment bisector that seperates both AB and BD into 2 congruent segments.And perpendicular lines form right angles.

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In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume t
Angelina_Jolie [31]

Answer:

P(X = 0) = 0.027

P(X = 1) = 0.189

P(X = 2) = 0.441

P(X = 3)= 0.343

Step-by-step explanation:

The probability mass function P(X = x) is the probability that X happens x times.

When n trials happen, for each x \leq n, the probability mass function is given by:

P(X = x) = pe_{n,x}.p^{x}.(1-p)^{n-x}

In which p is the probability that the event happens.

pe_{n,x}, is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

pe_{n,x} = \frac{n!}{x!}

The sum of all P(X=x) must be 1.

In this problem

We have 3 trials, so n = 3

The probability that a wafer pass a test is 0.7, so p = 0.7

Determine the probability mass function of the number of wafers from a lot that pass the test.

P(X = 0) = (0.7)^{0}.(0.3)^{3} = 0.027

P(X = 1) = pe_{3,1}.(0.7).(0.3)^{2} = 0.189

P(X = 2) = pe_{3,2}.(0.7)^{2}.(0.3) = 0.441

P(X = 3) = (0.7)^{3} = 0.343

5 0
4 years ago
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