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2 years ago

13

Uppose that you and a friend are playing cards and you decide to make a friendly wager. the bet is that you will draw two cards

without replacement from a standard deck. if both cards are diamonds, your friend will pay you $256$⁢256. otherwise, you have to pay your friend $14$⁢14.

1 answer:

hammer [34]2 years ago

7 0

Thats seem like a good trade but id dont get the question.

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A quadrilateral has vertices at $(0,1)$, $(3,4)$, $(4,3)$ and $(3,0)$. Its perimeter can be expressed in the form $a\sqrt2+b\sqr

seraphim [82]

Answer:

a + b = 12

Step-by-step explanation:

Given

Quadrilateral;

Vertices of (0,1), (3,4) (4,3) and (3,0)

$Perimeter = a\sqrt{2} + b\sqrt{10}$

Required

$a + b$

Let the vertices be represented with A,B,C,D such as

A = (0,1); B = (3,4); C = (4,3) and D = (3,0)

To calculate the actual perimeter, we need to first calculate the distance between the points;

Such that:

AB represents distance between point A and B

BC represents distance between point B and C

CD represents distance between point C and D

DA represents distance between point D and A

Calculating AB

Here, we consider A = (0,1); B = (3,4);

Distance is calculated as;

$Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

$(x_1,y_1) = A(0,1)$

$(x_2,y_2) = B(3,4)$

Substitute these values in the formula above

$Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

$AB = \sqrt{(0 - 3)^2 + (1 - 4)^2}$

$AB = \sqrt{( - 3)^2 + (-3)^2}$

$AB = \sqrt{9+ 9}$

$AB = \sqrt{18}$

$AB = \sqrt{9*2}$

$AB = \sqrt{9}*\sqrt{2}$

$AB = 3\sqrt{2}$

Calculating BC

Here, we consider B = (3,4); C = (4,3)

Here,

$(x_1,y_1) = B (3,4)$

$(x_2,y_2) = C(4,3)$

Substitute these values in the formula above

$Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

$BC = \sqrt{(3 - 4)^2 + (4 - 3)^2}$

$BC = \sqrt{(-1)^2 + (1)^2}$

$BC = \sqrt{1 + 1}$

$BC = \sqrt{2}$

Calculating CD

Here, we consider C = (4,3); D = (3,0)

Here,

$(x_1,y_1) = C(4,3)$

$(x_2,y_2) = D (3,0)$

Substitute these values in the formula above

$Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

$CD = \sqrt{(4 - 3)^2 + (3 - 0)^2}$

$CD = \sqrt{(1)^2 + (3)^2}$

$CD = \sqrt{1 + 9}$

$CD = \sqrt{10}$

Lastly;

Calculating DA

Here, we consider C = (4,3); D = (3,0)

Here,

$(x_1,y_1) = D (3,0)$

$(x_2,y_2) = A (0,1)$

Substitute these values in the formula above

$Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

$DA = \sqrt{(3 - 0)^2 + (0 - 1)^2}$

$DA = \sqrt{(3)^2 + (- 1)^2}$

$DA = \sqrt{9 + 1}$

$DA = \sqrt{10}$

The addition of the values of distances AB, BC, CD and DA gives the perimeter of the quadrilateral

$Perimeter = 3\sqrt{2} + \sqrt{2} + \sqrt{10} + \sqrt{10}$

$Perimeter = 4\sqrt{2} + 2\sqrt{10}$

Recall that

$Perimeter = a\sqrt{2} + b\sqrt{10}$

This implies that

$a\sqrt{2} + b\sqrt{10} = 4\sqrt{2} + 2\sqrt{10}$

By comparison

$a\sqrt{2} = 4\sqrt{2}$

Divide both sides by $\sqrt{2}$

$a = 4$

By comparison

$b\sqrt{10} = 2\sqrt{10}$

Divide both sides by $\sqrt{10}$

$b = 2$

Hence,

a + b = 2 + 10

a + b = 12

3 0

2 years ago

If a wheel with a radius of 80 inches spins at a rate of 50 revolutions per minute, find the approximate linear velocity in mile

Lubov Fominskaja [6]

$\bf \textit{arc's length}\\\\
s=rw\qquad 
\begin{cases}
r=radius\\
w=\textit{angular speed}
\end{cases}\qquad w=\cfrac{50 rev}{min}\cdot \cfrac{2\pi }{rev}
\\\\\\
w=\cfrac{100\pi }{min}\qquad s=80in\cdot \cfrac{100\pi }{min}\implies s=\cfrac{8000\pi\ in}{min}\\\\
-------------------------------\\\\
\textit{now to convert it to miles/hr}
\\\\\\
\cfrac{8000\pi\ in}{min}\cdot \cfrac{ft}{12in}\cdot \cfrac{mile}{5280ft}\cdot \cfrac{60min}{hr}\implies \cfrac{8000\pi \cdot 60\ in}{12\cdot 5280\ hr}$

3 0

3 years ago

Please someone help me

Anika [276]

2x^2 + 14x + 12 = 0

x^2 + 7x + 6 = 0

( x + 1 )( x + 6 ) = 0 ==》 x = - 1 Or x = - 6

6 0

2 years ago

The diameter of the wheels on your car is 25 inches. You are going to drive 458 miles today. Each of your wheels is going to tur

Kipish [7]

d = Diameter of wheels = 25 inches

s = Distance to be traveled by the wheels = 458 miles

Converting the miles to inches

$s=458\times 5280\times 12=29018880\ \text{inches}$

The distance traveled by the wheels in rotation is the circumference

$D=\pi d\\\Rightarrow D=\pi\times 25$

The number of rotations required to cover the distance would be

$\dfrac{s}{D}\\ =\dfrac{29018880}{\pi\times 25}\\ =369479.855599$

$1$ rotation is $360^{\circ}$ so

$369479.855599\times 360=133012748.016^{\circ}$

The number of rotations to cover the required distance is $133012748.016^{\circ}$

Learn more:

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4 0

2 years ago

A company rents out 19 food booths and 26 game booths at the county fair. The fee for a food booth is

rewona [7]

Answer:$4669

Step-by-step explanation:

175x19=3325+5(4)=3345

1300+6(4)=1324

5 0

2 years ago