The problem can be translated into an equation that is something like 4/5 + 3/x = 1/2
we cannot have x equal to zero because the number can be infinite.
So the LCD here is 10x, so multiply both sides by that to get:
8x + 30 = 5x
Subtract 5x and 30 from both sides:
3x = -30
divide:
x = -10
The solution isn't zero so there is a solution.
Excuse me,what do you mean by quadrant
Answer:
y = -2x -3
Step-by-step explanation:
- the altitude trough F is a perpendicular line to the line DE
- find slope of line DE
D ( x2 = -5, y2 = -1); E (x1 = 3, y1 = 3)
slope m = (y2-y1) / (x2-x1) = (-1-3) / (-5-3) = -4/ -8 = 1/2
-find equation of the altitude trough F
lines that are perpendicular have the slope negative reciprocal (negative reciprocal of 1/2 is -2)
y= -2x +b , for point F(1, -5)
-5 = -2*1 +b, add 2 to both sides
-5 +2 = b, combine like terms
-3 =b
equation of the altitude trough F is y = -2x -3
150
13+46= 59
59+87= 146
Round 46 to the nearest ten, which in this case would be 50 because the last number is larger than a 5.
Then add the 1 back in to make it 150.
Answer:
The answer is A
Step-by-step explanation:
hope this helps,
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