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gtnhenbr [62]
4 years ago
10

. How do you do this.

Mathematics
1 answer:
inn [45]4 years ago
7 0
Sin OH Cosin AH Tangent OA search "SOCAHTOA"
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Pls help plsssssssssssss
arlik [135]

Answer:

5

Step-by-step explanation:

i did the math

4 0
3 years ago
BY using eight eights  and addition only can you make 1000?????/
creativ13 [48]
If u add 125 times 8 it will equal 1000
becouse
8*125=1000
then
\frac{1000}{8} =125
you also can combine it (if this is what are you looking for..)
888+88+8+8+8=1000
or any other combination like:
88+888+8+8+8=1000
or:
8+8+888+8+88=1000
8 0
4 years ago
9+8{7•6-5[4+(3-2•1)]}=?​
34kurt

Answer:

145

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

9+8{7*6-5[4+(3-2*1)}]}

9+8{7*6-5[4+1]}

9+8{7*6-25}

9+8{42-25}

9+136

145

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

Please, please give brainliest, it would be greatly appreciated, I only a few more before I advance, thanks!

5 0
3 years ago
Use the Pythagorean theorem and the following diagram to help you find the area and perimeter of the following triangle. Please
Mekhanik [1.2K]

Answer:

Perimeter = 30

Area = 30

Step-by-step explanation:

(x+8)^2 -x^2 = 12^2

x^2 +16x +64 - x^2 = 144

16x+64=144

16x = 80

x = 5

Double check:

\sqrt{12^2 + 5^2} = (5+8)\\\sqrt{12^2 + 5^2} = 13\\13 = 13

Perimeter:

12+5+13=30

Area(\frac{1}{2}bh):

\frac{1}{2} × 12 × 5 = 30

5 0
3 years ago
Read 2 more answers
Given that AB parallels QR, AB bisects AE, QR bisects QT
enyata [817]

Answer:

  1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

  2. Translate A' to Q

Step-by-step explanation:

We notice the triangles have the same orientation, so no reflection or rotation is involved. The desired mapping can be accomplished by dilation and translation:

  1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

  2. Translate A' to Q

The result will be that ΔA"B"E" will lie on top of ΔQRT, as required.

5 0
3 years ago
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