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Nimfa-mama [501]
3 years ago
13

What percent is 48cm of 1.5 m​

Mathematics
2 answers:
Ann [662]3 years ago
6 0

First of all, recall that 1.5m is the same as 150cm.

Now, we simply build a proportion where we consider 48 to be 100, and wonder what 150 will be:

48\div 100 = 150 \div x

Solving for x, we have

x = \dfrac{150\cdot 100}{48}=\dfrac{15000}{48} = 312.5

Which actually makes sense, because we're stating that 1.5m is about 300% of 48cm, which means three times as much. Which is true, because three times 48cm means 144cm, which is about 1.5m

umka2103 [35]3 years ago
6 0

Answer:

  • <u>32%</u>

Step-by-step explanation:

To solve this problem, you must first have the numbers in the same units, that is, convert the meters to centimeters and operate with them or transform to meters and work with them, therefore, I decide to work with centimeters, like this:

  • 1.5 meters = 150 centimeters (each meter equals 100 centimeters)

Then, you can make a simple rule of three, where 150 centimeters corresponds to 100% and you look for the percentage of 48 centimeters:

  • 150 cm = 100%
  • 48 cm = X

So:

  • X = (48 * 100) / 150
  • X = 4800/150
  • <u>X = 32</u>

Therefore, <u>the percentage of 48 centimeters is equal to 32%</u>.

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UkoKoshka [18]

The matching of definitions and terms are done below.

  1. Some number increased by two ⇒ b + 2
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  5. An unknown value squared ⇒ y²

<h3>What is Algebra?</h3>

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

Match the verbal expression (term) with its algebraic expression (definition).

Some number increased by two ⇒ b + 2

A variable decreased by two ⇒ x – 2

Product of an unknown value and two ⇒ 2z

Quotient of some number and two ⇒ a ÷ 2

An unknown value squared ⇒ y²

More about the Algebra link is given below.

brainly.com/question/953809

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3 years ago
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Doss [256]

Answer:

When we have a rational function like:

r(x) = \frac{x + 1}{x^2 + 3}

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

x^2 = -3

x = √(-3)

This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

\frac{1}{4} = \frac{x + 1}{x^2 + 3}

We can multiply both sides by (x^2 + 3)

\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)

\frac{x^2 + 3}{4} = x + 1

Now we can multiply both sides by 4:

\frac{x^2 + 3}{4}*4 = (x + 1)*4

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Now we only need to solve the quadratic equation:

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a*x^2 + b*x + c = 0

the solutions are:

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a = 1

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x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

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