Answer:
1/18
Step-by-step explanation:
We are considering that we have 2 dices with 6 faces each (so, the probability to gettig any face in any dish is 1/6). To get an 11, we only have two ways to obtain it:
Dice 1= 6 and Dice 2 =5
or
Dice 1= 5 and Dice 2 =6
So, the probability of the event is given as:
P(Dice1=5 ∧ Dice2=6) ∪ P(Dice1=6 ∧ Dice2=5) = P(Dice1=5) x P(Dice2=6) + P(Dice1=6) x P(Dice2=5) = 1/6 x 1/6 + 1/6 x 1/6 = 1/36 + 1/36 = 2/36 = 1/18.
As 1/18 = 0,055, and 0,055 > 0,05, we consider the event as not significative (according to the definition of significance in the sentence).
Usually it's fun when you know what's going on....
1)
7/6d+4/3=-1/3
7/6d=-5/3
d=-5/3×6/7
d=-10/7
2)
5 1/2-u=9/4
11/2-u=9/4
22/4-u=9/4
13/4=u
3 1/4=u
3)
-m-7/8=-10
-m-7/8=-80/8
-m=-73/8
m=73/8 or 9 1/8
4)
2/7=4/5+9q
10/35=28/35+9q
-18/35=9q
q=-18/35×1/9
q=-2/35. Hope it help!
