(41 - 4/5) - (2/11 -14)

Manuela solved the equation 3−2|0.5x+1.5|=2 for one solution. Her work is shown below. 3−2|0.5x+1.5|=2 −2|0.5x+1.5|=−1 |0.5x+1.5

forsale [732]

Answer:

x=-4

Step-by-step explanation:

The given equation is

$3-2|0.5x+1.5|=2$

Subtract 3 from both sides.

$3-2|0.5x+1.5|-3=2-3$

$-2|0.5x+1.5|=-1$

Divide both sides by -2.

$\dfrac{-2|0.5x+1.5|}{-2}=\dfrac{-1}{-2}$

$|0.5x+1.5|=0.5$

If |x|=a, then x=a or x=-a.

$0.5x+1.5=\pm 0.5$

Case 1: $0.5x+1.5=0.5$

Subtract 1.5 from both sides.

$0.5x=0.5-1.5$

$0.5x=-1$

Divide both sides by 0.5.

$x=-2$

Case 2: $0.5x+1.5=-0.5$

Subtract 1.5 from both sides.

$0.5x=-0.5-1.5$

$0.5x=-2$

Divide both sides by 0.5.

$x=-4$

Therefore, one solution is x=-2 and other solution is x=-4.

5 0

4 years ago

Read 2 more answers

Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find

Papessa [141]

Answer:

1) $\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) $\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) $\text{P(at least two girls)}=\frac{1}{2}$

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To Find : The probability of each event.

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

1) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, BGG, GBB, GBG, GGB=6

$\text{P(at least one boy and one girl)}=\frac{6}{8}$

$\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, GBB=3

$\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

$\text{P(at least two girls)}=\frac{4}{8}$

$\text{P(at least two girls)}=\frac{1}{2}$

4 0

4 years ago

Read 2 more answers

Reduce 3272 to lowest terms.

zubka84 [21]

Answer:

If you reduce this to the lowest terms you get 4/9

Step-by-step explanation:

In order to simplify the fraction 32/72, you can divide each term by 8.

32/8 = 4

72/8 = 9

Therefore, we get 4/9

5 0

4 years ago

will mark brainliest. PROMISE!! A stick has a length of $5$ units. The stick is then broken at two points, chosen at random. Wha

Dmitry [639]

Answer:

0.16

Step-by-step explanation:

Length = 5 units
Number of broken sticks= 3
Equal lengths = 5 units/3

See the picture attached for reference.

As you see the best points are the green areas which covers 2 out of 5 zones.

Since it is same for both broken points, the probability of this is:

2/5*2/5 = 4/ 25 = 0.16

Answer is 0.16

6 0

4 years ago

Which set of side lengths is from a right triangle? A- 10,18,24 B- 9,12,15 C- 6,9,14 D- 4,8,10

dangina [55]

the sum of squares of two smaller sides equals the square of the largest side, it's right triangle

9^2 + 12^2 = 25^2
81 + 144 = 225
225 = 225

answer is B- 9,12,15

3 0

3 years ago