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vredina [299]
4 years ago
15

Last one ifr today ty !

Mathematics
1 answer:
timama [110]4 years ago
4 0

Answer:

The answer is D. -3, 6, 11

Step-by-step explanation:

A coefficient is a number used to multiply a variable.

Example: 6z means 6 times z, and "z" is a variable, so 6 is a coefficient. Variables with no number have a coefficient of 1.

Example: x is really 1x.

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ANSWER ASAP
Nadya [2.5K]

Bisector is simply a straight that divides the line (through which it's passing) into two equal halves. Or simply, it passes through the midpoint of any line. It may make any angle with the line through which it passes.

Perpendicular Bisector is also the same but the only difference is that it makes an angle of 90° with the line through which it passes or cuts.

3 0
1 year ago
How do i get a better grade if i'm failing
stellarik [79]
Ask for extra credit.

4 0
3 years ago
Read 2 more answers
If a worker can do his job in 5 hours, and a student can do the same job in 8 hours, what part of the work is left to finish aft
Aleks [24]

Answer:

Part of work left to finish after two work hours is 7/20

Step-by-step explanation:

Firstly, we need to calculate their joint work rate

That will be;

1/(1/5 + 1/8) = 1/(13/40) = 40/13

This means that they will complete the task in 40/13 hours

1 whole part takes 40/13

x part will take 2 hours

x * 40/13 = 2

40x = 26

x = 26/40

So the part that will be completed in two hours is 26/40

This means that the part left to complete will be:

1 - 26/40 = 14/40 = 7/20

8 0
3 years ago
Read 2 more answers
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
3 years ago
Can someone solve this with an explanation?
Readme [11.4K]
The correct answer is C

5 0
4 years ago
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