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atroni [7]
3 years ago
12

Plz help meee thanks

Mathematics
1 answer:
RoseWind [281]3 years ago
6 0

Answer:

Step-by-step explanation:

Ok, I’ve answered this questioned in a task of mine before, I believe it’s this here we go:

It should be 20 degrees is more than or equal to -60 degrees because the question is asking the relation BETWEEN the two and it has to be an inequality so yea!

I’m in 7th grade I KNOW YOUR PAIN!!!

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What is 0.00340.78 correct to 3 significant figures? explain your answer
timurjin [86]
What is 0.00340.78 correct to 3 significant figures?

a significant fugure is when the number lean solething ,so its can anyone except 0


so if we are reducing 0.00340.78 to 3 significant number

first we have to look for the significant nulber ,which are 3,4,7,8


so the answer can be 0.0034.7


hopefully this helps
7 0
3 years ago
X= <br><br> Y=<br><br> Z=<br><br> Pls help &gt;^&gt;
inysia [295]

Step-by-step explanation:

X = 50+45 = 95 exterior angle

y =95 + 52 = 147 exterior angle

Z = 180 Straight angle

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2 years ago
Use ratio language to describe the relationship between 2 dogs and 1 cat
Andrei [34K]
2:1 is the ratio

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3 years ago
Verify that the segments are parallel
kozerog [31]

Answer:

We know that lines AB and CD are parallel because if you expand them, we know they will never touch.

Step-by-step explanation:

4 0
3 years ago
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
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