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Airida [17]
3 years ago
10

What is the period of y = csc(x)?

Mathematics
2 answers:
matrenka [14]3 years ago
7 0

Answer:

2\pi.

Step-by-step explanation:

Please find the attachment.

We are asked to find the period of trigonometric function y=\text{csc}(x).

We know that period of a function is distance that is required for a function to complete one full cycle.

We know that the length of period of Cosecant is 2\pi, therefore, our answer is 2\pi.

lara31 [8.8K]3 years ago
4 0
The correct answer is 2 pi
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The surface areas of two similar hexagonal prisms are 882cm² and 1,058 cm²? What is the scale factor of the smaller
max2010maxim [7]

Answer:

scale factor of the smaller  prism to the larger prism is B. 21/23

Step-by-step explanation:

Given

surface areas of two similar hexagonal prisms are 882cm² and 1,058 cm²?

scale factor is ratio of sides of two similar objects

thus scale factor for given prism will be = side of smaller prism / side of larger prism

in general rule

If shape of solid has scale factor of k

scale factor of area = k²

scale factor of volume = k³

_____________________________

Given in the problem area of two prism is given

we know area = side^2

scale factor of area = k²

k^2 = area of smaller prism / area of larger prism

k^2 = 882 / 1058 = 441/529\\k = \sqrt{ 441/529} \\k = 21/23

Thus, correct option is B 21/23.

7 0
3 years ago
Hassan writes an algebraic expression with four terms. The x-term has a coefficient of 2 and the z-term has a coefficient of -1.
mixer [17]
Z(2/.0005)•Y maybe hope it helped
5 0
4 years ago
Help with number 16 (15 points!)
masha68 [24]

Answer:

-5≥x≤-1

Step-by-step explanation:

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6 0
3 years ago
Find the area of the
Flura [38]

Answer:

54.88 in^2

Step-by-step explanation:

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6 0
3 years ago
Given: △EDN∼△LKI, DQ , KO are altitudes, DN=12, KI=4, DQ=KO+6. Find: QN and OI.
fgiga [73]

Answer:

  • QN = 3√7
  • OI = √7

Step-by-step explanation:

The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...

  DQ = (3 units)·3 = 9 units

  KO = (3 units)·1 = 3 units

Then the base lengths QN and OI can be found from the Pythagorean theorem:

  KI² = KO² +OI²

  4² = 3² +OI²

  OI = √(16 -9)

  OI = √7

  QN = 3·OI = 3√7

8 0
3 years ago
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