Answer:
4
Step-by-step explanation:
This situation has two unknowns - the total number of half dollars and the total number of quarters. Because we have two unknowns, we will write a system of equations with two equations using the two unknowns.
- h+q=31 is an equation representing the total number of coins
- 0.50h+0.25q=11 is an equation representing the total value in money based on the number of coin. 0.50 and 0.25 come from the value of a half dollar and quarter individually.
We write the first equation in terms of q by subtracting it across the equal sign to get h=31-q. We now substitute this for h in the second equation.
0.50(31-q)+0.25q=11
15.5-0.50q+0.25q=11
15.5-0.25q=11
After simplifying, we subtract 15.5 across and divide by the coefficient of q.
-0.25q=-4.5
q=4
We now know of the 31 coins that 4 are quarters.
X and Y are supplementary, that means X + Y = 180.
But we have, X = Y +24, then
X + Y = Y + 24 + Y = 2Y + 24 = 180
Then
2Y = 156
Y = 78
Then X = 78 + 24 = 102.
Answer:
negative
Step-by-step explanation: it has negative signs
Answer:
A = 40/n
Therefore, she gave each friend 40/n ounces of jelly beans.
Step-by-step explanation:
Given;
Total amount of jelly beans To = 3 pounds = 3×16 ounces = 48 ounces
Total amount kept for family Ta = 8 ounces
Total amount given to friends = Ti
Number of friends = n
Amount given to each friend = A
Ti = To - Ta
A = Ti/n = (To-Ta)/n
A = (48 - 8)/n
A = 40/n
Therefore she gave each friend 40/n ounces of jelly beans.
The first choice can be any one of the 8 side dishes.
For each of these . . .
The 2nd choice can be any one of the remaining 7.
Total number of ways to pick 2 out of 8 = (8 x 7) = 56 ways .
BUT ...
That doesn't mean you can get 56 different sets of 2 side dishes.
For each different pair, there are 2 ways to choose them . . .
(first A then B), and (first B then A). Either way, you wind up with (A and B).
So yes, there are 56 different 'WAYS' to choose 2 out of 8.
But there are only 28 different possible results, and 2 'ways'
to get each result.
