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2 years ago

What is 43.29 rounded to the nearest tenth

1 answer:

3 0

The correct answer is 43.3.

Explanation:

When rounding a number, we first find the digit in the place value we're rounding to. In this problem, we are rounding to the tenths place; the digit in the tenths place is 2.

The next thing we do is look at the digit to the right of the place value we're rounding to. If this digit is 5 or more, we round our place value up; if it is 4 or less, we leave our place value alone. The number to the right of the 2 is 9; since this is in the "5 or more" category, we round the 2 up to 3.

The last step is to drop the digits to the right of our place value. This gives us our final answer of 43.3.

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If the price of gas is $9.475, what will the price be when we round it to the hundredths place?

nikklg [1K]

Answer:

$9.45

Step-by-step explanation:

if you round you get that

7 0

3 years ago

Read 2 more answers

What is 15 and 16 in a decimal

astra-53 [7]

Those are whole numbers so they can't be broken down into a decimal unless you just want 15.00 and 16.00 or could be .15 and .16

4 0

2 years ago

Xby the power of 5 times y to the power of 6 over 2 by the power of -2 times xby the power of 0times x by the power of 9

mars1129 [50]

Answer:

We have the sentence:

"X by the power of 5 times y to the power of 6 over 2 by the power of -2 times x by the power of 0times x by the power of 9"

Let's break it into parts.

"X by the power of 5 times y to the power of 6..."

This can be written as:

x^5*y^6

"... 2 by the power of -2 times x by the power of 0times x by the power of 9"

This can be written as:

2^(-2)*x^(0)*x^(9)

And we have the quotient between the first thing and the second thing, then the equation is:

$\frac{x^5*y^6}{2^{-2}*x^0*x^9}$

And any number by the power of 0 is equal to 1, then:

x^0 = 1, then we can rewrite the equation as:

$\frac{x^5*y^6}{2^{-2}*x^9}$

We can keep simplifying this.

We know that:

a^(-n) = (1/a)^(n)

Then:

2^(-2) = (1/2)^2 = 1/4

Then we get:

$\frac{x^5*y^6}{2^{-2}*x^9} = \frac{x^5*y^6}{x^9}*4$

And we also know that:

a^n/a^m = a^(n - m)

Then:

$\frac{x^5*y^6}{x^9}*4 = 4*y^6*\frac{x^5}{x^9} = 4*y^6*x^{5 - 9} = 4*y^6*x^{-4} = \frac{4*y^6}{x^4}$

And we can't simplify this anymore.

8 0

2 years ago

Expand (4x-3y)^4 using pascal's triangle ...?

jenyasd209 [6]

Using row 4:

coefficients are: 1, 4, 6, 4, 1 

a^4 + a^3b + a^2b^2 + ab^3 + b^4 

Now adding the coefficients: 

1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + 1b^4 

Substitute a and b: 

a = 4x 

b = -3y 

1(4x)^4 + 4(4x)^3(-3y) + 6(4x)^2(-3y)^2 + 4(4x)(-3y)^3 + 1(-3y)^4 

Now simplify the above: 

256x^4 - 768x^3y + 864x^2y^2 - 432xy^3 + 81y^4

8 0

2 years ago

Determine whether the equation below has a one solutions, no solutions, or an infinite number of solutions. Afterwards, determin

egoroff_w [7]

Answer:

no solution

Step-by-step explanation:

X cannot equal itself minus 5, in the same way if we replace it by let's say, 6...

6 does not equal 6-5 (1)........ and by the way in this specific equation 6 is just an example it does not matter what you replace it with, x can never = x-5

Hope this helped! Good Luck!

5 0

3 years ago