The length of the photograph is <u> 10 </u> inches.
Explanation:
Given, Width of a photograph is x.
Length of the photograph is 3 inches longer than its width. i.e. x + 3.
Area of the photograph = x(x+3)
If its area is 70 square inches, then
x(x+3)=70
![x^2 + 3x = 70](https://tex.z-dn.net/?f=x%5E2%20%2B%203x%20%3D%2070)
![x^2 + 3x-70 = 0](https://tex.z-dn.net/?f=x%5E2%20%2B%203x-70%20%3D%200)
![x^2 - 7x + 10x-70 = 0](https://tex.z-dn.net/?f=x%5E2%20-%207x%20%2B%2010x-70%20%3D%200)
x(x-7)+10(x-7)=0
(x+10)(x-7) =0
x+10=0; x-7 = 0
x = -10 and x = 7
Width of the photograph must not be in negative value. So, we can ignore –10.
Therefore, width of the photograph, x = 7 inches.
Now, the length of the photograph = 7 + 3 = 10 inches.
Thus, the required length of the photograph is 10 inches.
Solution
- The number line is a line that arranges numbers in ascending or increasing order from left to right.
- This implies that between any two numbers, the number to the right will always be greater than the number to the left.
- This order is illustrated in the figure below:
- Thus, we can proceed to solve the question given to us.
- 26.5 is to the right of 26.3. This implies that 26.5 is greater than 26.3. Another way to say this is that 26.3 is less than 26.5.
- Mathematically, we have
![26.3](https://tex.z-dn.net/?f=26.3%3C26.5)
Finial Answer
The answer is