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asambeis [7]
3 years ago
9

Excluded value of 9/2x

Mathematics
1 answer:
adell [148]3 years ago
3 0
X cannot be 0 because if it is, it would be undefined
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Please help me with this problem ​
andreyandreev [35.5K]

Answer:

<em>1</em><em>.</em><em>p</em><em>r</em><em>i</em><em>c</em><em>e</em><em>(</em><em>dollars)</em><em> </em><em>and </em><em>soccer</em><em> </em><em>ball</em>

<em>2</em><em>.</em><em>y</em><em>=</em><em>3</em><em>0</em><em> </em><em>and </em><em>x=</em><em>5</em>

<em>3</em><em>.</em><em> </em><em>I </em><em> </em><em>think </em><em>5</em><em> </em><em>or </em><em>3</em><em>0</em>

Step-by-step explanation:

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6 0
2 years ago
Truth or false every fraction has a limited number of equivalent frections .
xeze [42]

Answer:

False.

Since the number of numbers in the world is infinite, there can be an infinite number of equivalent fractions.

4 0
3 years ago
Read 2 more answers
Help will give crown
IrinaVladis [17]

Answer:

the answer of the question is C because 1/2=.5

5 0
3 years ago
Read 2 more answers
The answer to this question with the work
tester [92]
You would need to add 22 to 38 then divide that answer by 5 to get x
8 0
3 years ago
Use the discriminate to determine the number and the nature of the solutions of the giving equation.
PolarNik [594]

Answer:

Since b^2 -4ac = 256 we have 2 real distinct root roots

Step-by-step explanation:

4x^2+12x=7

We need to subtract 7 to get it in the proper form

4x^2+12x-7=7-7

4x^2+12x-7=0

The discriminant is b^2 -4ac

when the equation is ax^2 +bx+c

so a =4   b=12 and c=-7

(12)^2 - 4(4)(-7)

144 +112

256

If b^2 -4ac > 0 we have 2 real distinct roots

If b^2 -4ac = 0 we have one real root

If b^2 -4ac < 0 we have two complex root

Since b^2 -4ac = 256 we have 2 real distinct root roots

7 0
3 years ago
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