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3 years ago

Need Help QUICK, Will MARK BRAINLIEST!!!! LOTS OF POINTS

Mathematics

2 answers:

Ksju [112]3 years ago

7 0

Answer:

what is the question???

Step-by-step explanation:

Annette [7]3 years ago

3 0

Answer:

Step-by-step explanation:

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On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes

belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

$r = \frac{\Delta T_{X}}{\Delta T_{Y}}$

$r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}$

$r = 11\,\frac{^{\circ}X}{^{\circ}Y}$

The difference between current temperature in Y linear scale with respect to freezing point is:

$\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)$

$\Delta T_{Y} = 115\,^{\circ}Y$

The change in X linear scale is:

$\Delta T_{X} = r\cdot \Delta T_{Y}$

$\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)$

$\Delta T_{X} = 1265\,^{\circ}X$

Lastly, the current temperature on the X scale is:

$T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X$

$T_{X} = 1150\,^{\circ}X$

The current temperature on the X scale is 1150 °X.

5 0

3 years ago

Line n is parallel to Line P. Find the measure of each angle.<br> Please help

Margaret [11]

Answer:

m<1=140

m<2= 40

m<3= 140

m<4= 40

m<5=140

m<6= 40

m<7= 140

4 0

3 years ago

Read 2 more answers

Yoshi multiplied -6.2 by -0.14. His result was -0.868. Which statement likely describes the error he made in his calculation?

Digiron [165]

Step-by-step explanation:

The answer is letter B. Negative and Negative is Positive.

3 0

3 years ago

What’s the definition of net

timurjin [86]

Answer:

it is the surface of the 3d shape spread out like an blue print

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

I need an answer what is 1.03 ÷ (-10.3)=?

Sloan [31]

The answer is $- \frac{1}{10}$
To figure this out, convert both numbers to fractions. 1.03 = 1 $\frac{3}{100}$ and (-10.3) = -10 $\frac{3}{10}$ . Now, convert to improper fractions.
1 $\frac{3}{100} = [tex] \frac{103}{100}$
-10 $\frac{3}{10}$ = $- \frac{103}{10}$
Now, divide. Dividing fractions is the same as multiplying by the reciporical. So:
$-\frac{103}{10} \ becomes\ \frac{10}{103}$
$\frac{103}{100} *- \frac{10}{103} = -\frac{1030}{10300} = - \frac{1}{10}$

5 0

3 years ago