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VLD [36.1K]
3 years ago
6

Write a fraction greater than 1 for 6 using 9 as the denominator ​

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0
8/9. hope this helped
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In the function, 9 (2-) = 9 - 5x, what is the value of g (3)?
vekshin1

Answer: 53

Step-by-step explanation:

3 0
3 years ago
Sally is 1 year older than 3 times the age of joe.Chirs is 5 years younger than 6 times the age of joe.If sally and Chris are th
Sav [38]
S = sally C = Chris J = Joe
sally is one year older than 3 times the age of joe, so
s = 3j + 1
chris is 5 years younger than 6 times the age of jo, so
c = 6j - 5
sally and chris are the same age so
s = c so
3j + 1 = 6j - 5
-3j -3j
1 = 3j - 5
+5 +5
6 = 3j or
3j = 6
3j/3 = 6/3
j = 2

check
s = c
3(2) +1 = 6(2) - 5
6 + 1 = 12 - 5
7 = 7 correct✅
7 0
3 years ago
Read 2 more answers
student expanded an expression, as shown. Is the student's work correct? Explain why or why not. −6 ( 4x − 2 13 ) −6(4x) + 6 ( −
sleet_krkn [62]

Answer:

No, the student's work is not correct.

Step-by-step explanation:

Given : Student expanded an expression, as shown.

-6(4x-\frac{2}{13} )

-6(4x)+6(-\frac{2}{13} )

-24x-\frac{12}{13}

To find : Is the student's work correct?

Solution :

The expansion of student is not correct.

Follow the below steps to get correct solution and student mistake,

Step 1 - Write the expression,

-6(4x-\frac{2}{13} )

Step 2 - Apply distributive property, a(b+c)=ab+ac

=(-6)(4x)+(-6)(-\frac{2}{13})

Step 3 - Solve,

=-24x+\frac{12}{13}

The student was mistaken in step 2 in solving the sign.

4 0
3 years ago
Read 2 more answers
Perform a first derivative test on the function ​f(x)equals2 x cubed plus 3 x squared minus 120 x plus 6​; ​[minus5​,8​]. Bold
maria [59]

Answer:

a) Critical points

x = 4 and x = -5

b) x = 4 corresponds to a minimum point for the function f(x)

x = - 5 corresponds to a maximum point for the function f(x)

c) The minimum value of f(x) in the interval = -298

The maximum value of f(x) in the interval = 431;

Step-by-step explanation:

f(x) = 2x³ + 3x² - 120x + 6 in the interval [-5, 8]

a) To obtain the critical points, we need to obtain the first derivative of the function with respect to x. Because at critical points of a function, f(x), (df/dx) = 0

f'(x) = (df/dx) = 6x² + 6x - 120 = 0

6x² + 6x - 120 = 0

Solving the quadratic equation,

x = 4 or x = -5

The two critical points, x = 4 and x = -5 are in the interval given [-5, 8] (the interval includes -5 and 8, because it's a closed interval)

b) To investigate the nature of the critical points, we obtain f"(x)

Because f'(x) changes sign at the critical points

If f"(x) > 0, then it's a minimum point and if f"(x) < 0 at c, then it's a maximum point.

f"(x) = (d²f/dx²) = 12x + 6

at critical point x = 4

f"(x) = 12x + 6 = 12(4) + 6 = 54 > 0, hence, x = 4 corresponds to a minimum point.

at critical point x = -5

f"(x) = 12x + 4 = 12(-5) + 4 = -56 < 0, hence, x = -5 corresponds to a maximum point.

c) At x = 4,

f(x) = 2x³ + 3x² - 120x + 6 = 2(4)³ + 3(4)² - 120(4) + 6 = -298

At x = - 5

f(x) = 2x³ + 3x² - 120x + 6 = 2(-5)³ + 3(-5)² - 120(-5) + 6 = 431

7 0
3 years ago
(6•11)2 •2-4(-2+14)2-12 simplest terms
Ksju [112]

Answer:

\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left[-10-\left(-6\right)\right]}{\left[4+5\right]\div \left[4^2\:−\:3^2\left(4−3\right)−8\right]+12}

Step-by-step explanation:

\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{4+5}{\left(4^2-3^2\left(4-3\right)-8\right)+12}}

8 0
3 years ago
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