Step-by-step explanation:
Q1 . (f+g)(x) = f(x) + g(x)
=4x-4 +2x^2 -3x
= 2x^2 + x -4
Q2. (f-g)(x) = f(x) - g(x)
= 2x^2−2 - (4x+1)
= 2x^2 -2 -4x -1
= 2x^2 - 4x -3
Q3. h(x)=3x−3 and g(x)=x^2+3
(h.g)(x) = h(x) × g(x)
= (3x-3) × (x^2 + 3)
=3x^3 -3x^2 + 9x -9
Q4.f(x)=x+4 and g(x)=x+6
(f/g)(x) = f(x) ÷ g(x)
= x+4 / x+6
the domain restriction is x>-6
x<-6
x doesn't equal (-6)
Answer:
In Mathematics Geometry,<em> lateral face</em> is said be the side of a 3D-figure in that is not a base.
Please check the attached figure to visual the concept.
Step-by-step explanation:
In Mathematics Geometry,<em> lateral face</em> is said be the side of a 3D-figure in that is not a base.
The faces in in a prism or pyramid which are not bases are basically the lateral faces.
For example, the lateral faces are basically parallelograms in Triangular prism which are not the bases.
Please check the attached figure to visual the concept.
Answer:
4
Step-by-step explanation:
I'm pretty sure theres a graph to this so....
The given parabolic graph of quadratic function
To find:What is F(6) for the quadratic function
Solution:We have given graph of quadratic function
there is a different value for Y and a different value for X
For f(6)
here X=6, need to find graph of quadratic function
X=6
f(6)=4
Y=4
Your welcome :)
Answer:
210
Step-by-step explanation:
x = num of adults
x + 7.5x = 238
8.5x = 238
x = 28
#students = 238-x
= 210