Answer:
Option B is correct.
Step-by-step explanation:
We have given a triangle ABC and EDC please look at the figure
We can see that AE and BD are transversal therefore, ∠EAB=∠AED being alternate interior angles
And ∠ACB=∠DCE are vertically opposite angles hence, equal
So, by AA similarity postulate the above to triangles are similar
ΔABC 
ΔEDC
Therefore, Option B is correct that is Triangle ABC is similar to triangle EDC , because m∠3 = m∠4 and m∠1 = m∠5
NOTE: m∠3 = m∠4 corresponds to m∠ACB=m∠DCE
And m∠1 = m∠5 corresponds to m∠EAB=m∠AED
<h3>Option C is correct</h3>
<h3>Let us see the verification;</h3>
<h2>Hence, Proved ✔︎</h2>
Answer:
AD= 5.82 units (3 s.f.)
Step-by-step explanation:
Please see attached picture for full solution.
*skipped these steps in the beginning:
∠ABC +∠ABD= 180° (adj. ∠s on a str. line)
90° +∠ABD= 180°
Answer:
p=5
Step-by-step explanation:
3p-7+p=13
Add like terms.
3p+p-7=13
4p-7=13
Add 7 to both sides.
4p-7+7=13+7
4p=20
Divide 4 from both sides.
=
p=5
Hope this helps!
If not, I am sorry.
ANSWER:
125/2 =125/2
PROVED
STEP BY STEP EXPLANATION
PUTTING THE VALUE OF X, WE HAVE
1/2×5×5×5=125/2
1/2×125=125/2
125/2=125/2
HENCE ,L.H.S =R.H.S
PROVED.
HOPE THIS WILL HELP YOU
