Answer:
please mark as brainliest!!
Explanation:
public class SumOfDigits{ public static void main(String args[]) { Scanner sc = new Scanner(System.in); System.out.println("Please enter a number to calculate sum of digits"); int number = sc.nextInt(); // Remember number/10 reduces one digit from number // and number%10 gives you last digit int sum = 0; int input = number; while (input != 0) { int lastdigit = input % 10; sum += lastdigit; input /= 10; } System.out.printf("Sum of digits of number %d is %d", number, sum); // closing Scanner to prevent resource leak sc.close(); } }
Answer:
second_int = "Enter the second integer: "
usernum = int(input("Enter the first integer: "))
x = int(input(second_int))
usernum = usernum // x
print(usernum, end= ' ')
usernum = usernum // x
print(usernum, end= ' ')
usernum = usernum // x
print(usernum, end= ' ')
usernum = usernum // x
print(usernum)
Explanation:
im good
Life Cycle Sustainment Plan (LCSP) is the document that the program manager (pm) addresses the demilitarization and disposal requirements.
<h3>What is Life Cycle Sustainment Plan?</h3>
Life Cycle Sustainment Plan is a plan or service that works during the trade of weapons or system work regarding militarization. This system works on the development and handling of the weapon system.
So, Life Cycle Sustainment Plan will be used in the demilitarization and management requirements.
Thus, the name of the document program is Life Cycle Sustainment Plan.
To learn more about Life Cycle Sustainment Plan, refer to the below link:
brainly.com/question/1272845?referrer=searchResults
#SPJ1
The answer to your question is b crowding out effect
Answer:
% here x and y is given which we can take as
x = 2:2:10;
y = 2:2:10;
% creating a matrix of the points
point_matrix = [x;y];
% center point of rotation which is 2,2 here
x_center_pt = x(2);
y_center_pt = y(2);
% creating a matrix of the center point
center_matrix = repmat([x_center_pt; y_center_pt], 1, length(x));
% rotation matrix with rotation degree which is 45 degree
rot_degree = pi/4;
Rotate_matrix = [cos(rot_degree) -sin(rot_degree); sin(rot_degree) cos(rot_degree)];
% shifting points for the center of rotation to be at the origin
new_matrix = point_matrix - center_matrix;
% appling rotation
new_matrix1 = Rotate_matrix*new_matrix;
Explanation:
We start the program by taking vector of the point given to us and create a matrix by adding a scaler to each units with repmat at te center point which is (2,2). Then we find the rotation matrix by taking the roatational degree which is 45 given to us. After that we shift the points to the origin and then apply rotation ans store it in a new matrix called new_matrix1.
