Question

The base of the right triangle drawn in the regular octagon measures 0.7 cm.

Answer 1

Just took the test, its 11.2

Answer 2

we know that

the perimeter of the regular octagon is equal to

$P=8b$

where

b is the length side of the regular octagon

In the right triangle of the figure

$\frac{b}{2}=0.7$

Solve for b

$b=2*0.7=1.4\ cm$

substitute the value of b in the formula

$P=8b=8*1.4=11.2\ cm$

therefore

the answer is

the perimeter of the octagon is $11.2\ cm$