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Arlecino [84]
2 years ago
9

Kip bought one and four sixths pounds of toffee. He gave five sixths of a pound to his friend. How much toffee does Kip have lef

t?
five sixths pound
four sixths pound
two and three sixths pounds
one and one sixth pounds
Mathematics
2 answers:
Ray Of Light [21]2 years ago
6 0

Answer:

5/6

Step-by-step explanation:

1 4/6-5/6=?

1 4/6=10/6

10/6-5/6=5/6

givi [52]2 years ago
4 0

Answer:

five sixths pound

Step-by-step explanation:

Kip bought 1\frac{4}{6} pounds of toffee. He gave \frac{5}{6} of a pound to his friend. How much toffee does he have left?

The narrator is asking how much he has left after giving some toffee to his friend, that means we have to subtract.

1\frac{4}{6} - \frac{5}{6}

We already have an equal denominator so we can just subtract.

\frac{10}{6}-\frac{5}{6} = \frac{5}{6}

Kip has \frac{5}{6} pounds left.

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Se tiene un rectángulo cuya base mide el doble que su altura y su área es 12
irina [24]

Answer:

Part 1) The perimeter is  P=6\sqrt{6}\ cm

Part 2) The diagonal is d=\sqrt{30}\ cm

Step-by-step explanation:

<u><em>The question in English is</em></u>

You have a rectangle whose base is twice the height and its area is 12

square centimeters. Calculate the perimeter of the rectangle and its diagonal

step 1

Find the dimensions of rectangle

we know that

The area of rectangle is equal to

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A=12\ cm^2

so

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substitute equation B in equation A

(2h)h=12\\2h^2=12\\h^2=6\\h=\sqrt{6}\ cm

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b=2\sqrt{6}\ cm

step 2

Find the perimeter of rectangle

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P=2(b+h)

substitute

P=2(2\sqrt{6}+\sqrt{6})\\P=6\sqrt{6}\ cm

step 3

Find the diagonal of rectangle

Applying the Pythagorean Theorem

d^2=b^2+h^2

substitute

d^2=(2\sqrt{6})^2+(\sqrt{6})^2

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3 years ago
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