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jolli1 [7]
3 years ago
14

A particular dress requires 4 1/4 yards of fabric for manufacturing. If the matching jacket requires 1/6 yards less fabric, how

much fabric is needed for both pieces? Need answer now!
Mathematics
2 answers:
ASHA 777 [7]3 years ago
6 0

Answer:

4  5/12 + 4 1/4  

Step-by-step explanation:

4  1/4 - 1/6 - you have to turn the mixed # into improper fraction  -  17/4,

17/4 - 1/6 = 4 5/12

4 5/12 + 4 1/4  8 2/3

8 2/3 is the answer i hope this helps lol, :)

sveta [45]3 years ago
5 0

Answer: A total of 8 1/3 yards of fabric is needed for both pieces.

Step-by-step explanation: First, you must subtract 1/6 from 4 1/4 to figure out how many yards of fabric is needed for the matching jacket. To do this, you have to find common denominators for each fraction. Since the fractions have a least common denominator of 12, change each fraction to satisfy this new denominator: 1/6 changes to 2/12 and 4 1/4 changes to 4 3/12. Now, you must subtract: 4 3/12 - 2/12 = 4 1/12. Therefore, the matching jacket requires 4 1/12 yards of fabric. Next, add the amount of fabric for the dress (4 3/12) to the amount of fabric for the matching jacket (4 1/12): 4 3/12 + 4 1/12 = 8 4/12. Simplify 8 4/12 to get a final answer of 8 1/3 yards of fabric in total.

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The information given below was extracted from the accounting records of Sunray Traders, a partnership business with Sunny and R
Crank

The preparation of the Profit and Loss Appropriation Account for the year ended February 28, 2022, is as follows:

<h3>What is the Profit and Loss Appropriation Account?</h3>

A profit and loss appropriation account is a special account prepared for the distribution of the partnership's profit and loss for the period.

For Sunray Traders Partnership, the profit and loss appropriation account is detailed below.

<h3>Profit and Loss Appropriation Account</h3>

For the year ended February 28, 2022

                                        Sunny      Raymond       Total

Net Profit for the year                                         R900,000

Interest on capital       R84,000      R24,000    (R108,000)

Annual Salaries         R307,500    R246,000   (R553,500)

Share of profits         R119,250     R119,250  (R238,500)

<h3>Question Completion:</h3>

(c) The partners are entitled to the following monthly salaries from 01 March 2021 to 30 November 2021:

Sunny R25 000 Raymond R20 000

Note: The salaries of the partners were increased by 10% with effect from 01 December 2021.

d) The balance of the profit and loss must be shared equally between Sunny and Raymond.

Prepare the Profit and Loss Appropriation Account for the year ended February 28m 2022.

<h3>Data and Calculations:</h3>

                                              DEBIT        CREDIT

Capital: Sunny                                   R1 000 000

Capital: Raymond                                  600 000

Current a/c: Sunny (01 March 2021)       40 000

Current a/c: Raymond (01 March 2021) 60 000

Drawings: Sunny             R300 000

Drawings: Raymond         400 000

Net profit = R900 000

Sunny's Salaries = R307,500 (R25,000 x 9 + R25,000 x 1.1 x 3)

Raymond Salaries = R246,000 (R20,000 x 9 + R20,000 x 1.1 x 3)

<h3>Capital Accounts Balances:</h3>

                                        Sunny      Raymond       Total

Capital accounts      R1 000 000  R600 000   R1 600 000

Drawings accounts       300 000    400 000        700 000

Net Capital accounts R700 000  R200 000     R900 000

Interest on capital       R 84 000    R24 000       R108 000

Thus, the profit and loss of Sunray Traders Partnership are shared equally as agreed.

Learn more about partnership accounts at brainly.com/question/22693552

#SPJ1

3 0
1 year ago
Madelyn's car used 6 gallons of gas to drive 126 miles. At what rate does her car use
Reil [10]

Answer:

Step-by-step explanation:

You are given    GALLONS     and   MILES

   you want to find MILES / GALLON

     so just put those numebrs in

         MILES / GALLON =  126 miles / 6 gallons = 21 m/g  (or 21 MPG)

4 0
3 years ago
To decorate for a party, Simon needs 1,850 centimeters of colorful streamers. If the ratio of meters to centimeters is 1 : 100,
Art [367]
He needs 18.5 <span>meters of streamers
Just divide 1,850 by 100...
...and you'll get 18.5</span>
5 0
2 years ago
Read 2 more answers
If a cat falls out of a tree, it has a probability of 0.92 that it will land
Alex_Xolod [135]

The probability that the cat lands on its feet both times it falls out of a tree is 0.85

<h3>How to determine the probability?</h3>

The probability that the cat lands on its feet is given as:

P(Feet) = 0.92

The probability that it lands on its feet twice is calculated using:

P = P(Feet) * P(Feet)

So, we have:

P = 0.92 * 0.92

Evaluate

P = 0.85

Hence, the probability is 0.85

Read more about probability at

brainly.com/question/251701

#SPJ1

3 0
1 year ago
John, Sally, and Natalie would all like to save some money. John decides that it
brilliants [131]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2)  y=100x+300

Part 3) \$12,300

Part 4) \$2,700

Part 5) Is a exponential growth function

Part 6) A=6,000(1.07)^{t}

Part 7) \$11,802.91

Part 8)  \$6,869.40

Part 9) Is a exponential growth function

Part 10) A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

Part 11)  \$13,591.41

Part 12) \$6,107.01

Part 13)  Natalie has the most money after 10 years

Part 14)  Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

m=\$100\ per\ month

The y-intercept or initial value is

b=\$300

so

y=100x+300

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

10\ years=10(12)=120 months

For x=120 months

substitute in the linear equation

y=100(120)+300=\$12,300

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

so

2\  years=2(12)=24\ months

For x=24 months

substitute in the linear equation

y=100(24)+300=\$2,700

Part 5) What type of exponential model is Sally’s situation?

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt} 

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

P=\$6,000\\ r=7\%=0.07\\n=1

substitute in the formula above

A=6,000(1+\frac{0.07}{1})^{1*t}\\  A=6,000(1.07)^{t}

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute  the value of t in the exponential growth function

A=6,000(1.07)^{10}=\$11,802.91 

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute  the value of t in the exponential growth function

A=6,000(1.07)^{2}=\$6,869.40

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt} 

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

P=\$5,000\\r=10\%=0.10

substitute in the formula above

A=5,000(e)^{0.10t}

Applying property of exponents

A=5,000(1.1052)^{t}

 therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

A=5,000(e)^{0.10*10}=\$13,591.41

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

A=5,000(e)^{0.10*2}=\$6,107.01

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

3 0
3 years ago
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