58=12+2x
Subtract 12 from each side
46=2x
Divide each side by two
23=x
The cost of each pass is $23
bearing in mind that perpendicular lines have negative reciprocal slopes, so
![\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{10em}\stackrel{slope}{y=\stackrel{\downarrow }{-\cfrac{1}{3}}x-1} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20slope-intercept~form%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y%3D%5Cunderset%7By-intercept%7D%7B%5Cstackrel%7Bslope%5Cqquad%20%7D%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7Bm%7Dx%2B%5Cunderset%7B%5Cuparrow%20%7D%7Bb%7D%7D%7D%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D~%5Chspace%7B10em%7D%5Cstackrel%7Bslope%7D%7By%3D%5Cstackrel%7B%5Cdownarrow%20%7D%7B-%5Ccfrac%7B1%7D%7B3%7D%7Dx-1%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
so we're really looking for a line whose slope is 3 and runs through (1,5)
Amount of the job done after 2 hours:
2(1/6 + 1/8)
2(4/24 + 3/24)
2(7/24)
7/12 (amount of job finished)
.
amount of job left to do:
1 - 7/12
12/12 - 7/12
5/12 (remaining)
.
Let x = time (hours) slower press takes to finish job
then
x(1/6) = 5/12
multiplying both sides by 6:
x = 5/12 *6
x = 5/2 hours
or
x = 2 hours and 30 minutes
The slower press (8-hour press), will take h 3 hours, 20 minutes to complete the job
Answer:
Step-by-step explanation:
eq. of line parallel to y=34x-9 is y=34 x+k
∵ it passes through (-8,-18)
∴-18=34×-8+k
k=-18+272
k=254
so reqd. eq. is y=34 x+272
