Let's examine the given function first:
f(x) = x^2 + 1 is the same as f(x) = 1(x-0)^2 + 1.
The vertex of the graph of this function is at (0, 1).
Let x=0 to find the y-intercept: f(0)=0^2+1 = 1; y-int. is at (0,1) (which happens to be the vertex also)
Comparing f(x) = x^2 + 1 to y = x^2, we see that the only difference is that f(x) has a vertical offset of 1. So: Graph y=x^2. Then translate the whole graph UP by 1 unit. That's it. Note (again) that the vertex will be at (0,1), and (0,1) is also the y-intercept.
Answer:
y = 2x-10
Step-by-step explanation:
just that is the way
K is equal to 2.
You have to move the 4 to the other side and change the addition sign to subtraction. After that, you have to subtract 8 and 4 which will give you 4 and 4 divided by 2 is 2 which means that k equals 2.
