Answer:
The roots are;
x = (2 + i)/5 or (2-i)/5
where the term i is the complex number representing the square root of -1
Step-by-step explanation:
Here, we want to use the completing the square method to solve the quadratic equation;
f(x) = -5x^2 + 4x -1
Set the function to zero
0 = -5x^2 + 4x - 1
So;
-5x^2 + 4x = 1
divide through by the coefficient of x which is -5
x^2 - 4/5x = -1/5
We now take half of the coefficient of x and square it
= -2/5^2 = 4/25
add it to both sides
x^2 - 4x/5 + 4/25= -1/5 + 4/25
(x- 2/5)^2 = -1/5 + 4/25
(x - 2/5)^2 = -1/25
Take the square root of both sides
x - 2/5 = √( -1/25
x - 2/5 = +i/5 or -i/5
x = 2/5 + i/5 or 2/5 - i/5
Answer:
Step-by-step explanation:
Let the original number = x

x=98.0
x=98
Answer:
98% confidence interval of the true proportion of all Americans who celebrate Valentine's Day
(0.3672 , 0.7328)
Step-by-step explanation:
<u><em>Explanation:</em></u>-
Given Random sample size n =40
Sample proportion

98% confidence interval of the true proportion of all Americans who celebrate Valentine's Day

The Z-value Z₀.₉₈ = Z₀.₀₂ = 2.326
98% confidence interval of the true proportion of all Americans who celebrate Valentine's Day

( 0.55 - 0.1828 , 0.55 + 0.1828)
(0.3672 , 0.7328)
PROBLEM ONE
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Solving for x in 2x + 5y > -1.
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Step 1 ) Subtract 5y from both sides.
2x + 5y > -1
2x + 5y - 5y > -1 - 5y
2x > -1 - 5y
Step 2 ) Divide both sides by 2.
2x > -1 - 5y


So, the solution for x in 2x + 5y > -1 is...

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Solving for y in 2x + 5y > -1.
•
Step 1 ) Subtract 2x from both sides.
2x + 5y > -1
2x - 2x + 5y > -1 - 2x
5y > -1 - 1x
Step 2 ) Divide both sides by 5.
5y > -1 - 1x


So, the solution for y in 2x + 5y > -1 is...

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PROBLEM TWO
•
Solving for x in 4x - 3 < -3.
•
Step 1 ) Subtract 3 from both sides.
4x - 3 < -3
4x -3 - 3 < -3 - 3
4x < 0
Step 2 ) Divide both sides by x.
4x < 0

x < 0
So, the solution for x in 4x - 3 < -3 is...
x < 0
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- <em>Marlon Nunez</em>