Question

How do you solve 6x^2 plus 5x=20 algebraically?

Answer 1

I believe the answer would be
$x = \frac{ - 5 + \sqrt{505} }{12} and \: \frac{ - 5 - \sqrt[]{505} }{12}$
Good Luckkk.:-)

Step 1 move all terms to one side
example: 6x^2+5x-20=0
step 2 use the quadratic formula.
How: In general ax^2+c=0, there exists two solutions.

Next: In this case a=6 , b=5, c= -20

Last step: which is Simplify leaves you with the top answer!