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Tems11 [23]
3 years ago
15

To ensure he never eats the whole cake, Bobby only decides to eat half of what’s left for each serving. If 2/3 of the cake are l

eft initially, and no one else but Bobby eats the cake, how much of the cake will Bobby have eaten by his 5th serving?
Mathematics
1 answer:
siniylev [52]3 years ago
4 0
1st serving: 2/3 * 1/2 = 2/6 or 1/3
2nd serving: 1/3 * 1/2 = 1/6
3rd serving: 1/6 * 1/2 = 1/12
4th serving: 1/12 * 1/2 = 1/24
5th serving: 1/24 * 1/2 = 1/48

1/3 + 1/6 + 1/12 + 1/24 + 1/48 
1/3 * 16/16 = 16/48
1/6 * 8/8 = 8/48
1/12 * 4/4 = 4/48
1/24 * 2/2 = 2/48
1/48 * 1/1 = 1/48

16/48 + 8/48 + 4/48 + 2/48 + 1/48 = 31/48

Bobby ate 31/48 of the cake in total.
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Miles using 4.5 gallons = 144 miles
Miles using 1 gallon
(144 miles / 4.5 gallons)
32 miles / gallon
3 0
2 years ago
Read 2 more answers
Hi I need to know the slope(m) before 11:00 I know the y-intercept(b) is -3
Alexxandr [17]

Answer:

slope is 2/3

Step-by-step explanation:

y=mx + b where m is the slope

6 0
2 years ago
Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro
Ugo [173]

Answer:

Side\ B = 6.0

\alpha = 56.3

\theta = 93.7

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with \alpha, \beta, \theta

[See Attachment for Triangle]

A = 10cm

C = 12cm

\beta = 30

What the question is to calculate the third length (Side B) and the other 2 angles (\alpha\ and\ \theta)

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

B^2 = A^2 + C^2 - 2ABCos\beta

Substitute: A = 10,  C =12; \beta = 30

B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30

B^2 = 100 + 144 - 240*0.86602540378

B^2 = 100 + 144 - 207.846096907

B^2 = 36.153903093

Take Square root of both sides

\sqrt{B^2} = \sqrt{36.153903093}

B = \sqrt{36.153903093}

B = 6.0128115797

B = 6.0 <em>(Approximated)</em>

Calculating Angle \alpha

A^2 = B^2 + C^2 - 2BCCos\alpha

Substitute: A = 10,  C =12; B = 6

10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 180 - 144 *Cos\alpha

Subtract 180 from both sides

100 - 180 = 180 - 180 - 144 *Cos\alpha

-80 = - 144 *Cos\alpha

Divide both sides by -144

\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}

\frac{-80}{-144} = Cos\alpha

0.5555556 = Cos\alpha

Take arccos of both sides

Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)

Cos^{-1}(0.5555556) = \alpha

56.25098078 = \alpha

\alpha = 56.3 <em>(Approximated)</em>

Calculating \theta

Sum of angles in a triangle = 180

Hence;

\alpha + \beta + \theta = 180

30 + 56.3 + \theta = 180

86.3 + \theta = 180

Make \theta the subject of formula

\theta = 180 - 86.3

\theta = 93.7

5 0
3 years ago
I'll give brainlist for this !!!!!!!!
castortr0y [4]

Answer:

The first error in the bill is +8

because when two opposite signs of number are multiplied so the result is always negative.

so,

2 × -4 = -8

instead of 8 their should be -8.

hope this answer helps you dear...take care!

4 0
2 years ago
35 POINTS!!!!!!!!!!!!!!!!!!!
loris [4]

The answer is C

see attached picture:

4 0
2 years ago
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