
Use the rational zero theorem
In rational zero theorem, the rational zeros of the form +-p/q
where p is the factors of constant
and q is the factors of leading coefficient

In our f(x), constant is 2 and leading coefficient is 14
Factors of 2 are 1, 2
Factors of 14 are 1,2, 7, 14
Rational zeros of the form +-p/q are

Now we separate the factors


We ignore the zeros that are repeating

Option A is correct
Answer:
y=mx+b sdi c xc xx cx cx cxc xc 87
Step-by-step explanation:
Your answer is 8,000 minus 6 & 4
Step-by-step explanation:
Answer:
x=4 and y=2
Step-by-step explanation:
Name the triangles as ABC and DEF,
Now, since both the triangles are congruent by HL rule, therefore
(1)
and
(2)
Substituting the value of
in equation (1), we get



Therefore, Putting y=2 in equation (2),
