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2 years ago

What is the solution of x - 13 =5

Mathematics

2 answers:

Igoryamba2 years ago

8 0

If you're looking for x then it would be x=18 since you add 13 to both sides to have x alone

Artyom0805 [142]2 years ago

3 0

X-13=5
+13=+13
x =18
the answer is x=8

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Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th

Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
Symmetry: For all x,y, if xRy then yRx.
Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

By 3:00 pm, the temperature had increased by another 5%F. Was the temperature at 3:00 pm positive or negative?How do you know?Wh

victus00 [196]

Answer:

Part a) The temperature at noon was -3°F

Part b) The temperature at 3:00 pm was +2°F

Part c) The temperature at 11:00 pm was -6°F

Step-by-step explanation:

The complete question is

When Leo woke up he saw that the temperature was -8°F. By noon the temperature has increased 5°F. Part a) What was the temperature at noon?

Part b) By 3:00 pm, the temperature increased by another 5 degrees Fahrenheit was the temperature at 3:00 pm positive or negative?

Part c) By 11:00 pm, the temperature had dropped 8°F. Was the

temperature at 11:00 PM positive or negative? Explain.

Part a) we know that

You can use a number line to adds the numbers

-8+5=-3°F

therefore

The temperature at noon was -3°F

Part b) we know that

the temperature increased by another 5 degrees

You can use a number line to adds the numbers

-3+5=+2°F

therefore

The temperature at 3:00 pm was +2°F

Part c) we know that

the temperature had dropped 8°F

You can use a number line to adds the numbers

2-8=-6°F

therefore

The temperature at 11:00 pm was -6°F

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