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salantis [7]
3 years ago
9

Find the domain of f(x)=7/x^2-9

Mathematics
1 answer:
LiRa [457]3 years ago
8 0

the domain of the equation is this

{ x | x ≠ 0 }                                                                                                                                      

but I'm not entirely sure this is correct

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The area is 12x^2-19x-21
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The following graph shows a bus’s record of the number of passengers it picked up over the course of a day. A bar graph titled B
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Answer:

(A)55

Step-by-step explanation:

\left|\begin{array}{c|ccccccccccccccc}x(Time)&7&8&9&10&11&12&1&2&3&4&5&6\\y(Passsengers)&40&62&58&43&36&55&41&28&31&37&75&64\end{array}\right|

From the values on the graph which is presented in the table above, the number of people who rode the bus during the 12.00 hour is 55.

<u>The correct option is A.</u>

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3 years ago
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(1 point) Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference betw
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Answer:

a. \frac{dT}{dt}=k(T-Tm); T(0)=190

b. C_{0}=122

c. k=-0.00259

d. t=153.39838\\ minutos

Step-by-step explanation:

a. Newton's law of cooling states that the speed with which a body is cooled is proportional to the difference between its temperature and that of the medium in which it is found. Then, the initial value problem is given by:

Tm=68

\frac{dT}{dt}=k(T-Tm); T(0)=190

b. The differential equation obtained is a differential equation of separable variables:

\frac{dT}{T-Tm}=kdt\\\\\int {\frac{dT}{T-Tm}}=\int{kdt}\\\\Ln|T-Tm|=kt+C\\\\T(t)=C_{0}e^{kt}+Tm=C_{0}e^{kt}+68\\\\T(0)=C_{0}e^{k(0)}+68=190\\\\C_{0}=122

c. After 33 minutes of serving the coffee has cooled to 180°:

T(33)=122e^{33k}+68=180\\\\e^{33k}=\frac{112}{122}\\\\33k=Ln(\frac{112}{122})\\\\k=-0.00259

d.

150=122e^{-0.00259t}+68\\\\Ln(\frac{150-68}{122})=-0.00259t\\\\t=153.39838\\\\

8 0
3 years ago
Please help in maths
Readme [11.4K]

The equivalent expressions of 22c + 33d are (a), (c) and (e)

<h3>How to determine the equivalent expressions?</h3>

The expression is given as:

22c + 33d

Factor out 11 from the expression

11(2c + 3d)

Multiply by 1

1 * 11(2c + 3d)

Express 1 as -1 * -1

-1 * -1 * 11(2c + 3d)

Evaluate the product

(-11) * (-2c - 3d)

Also, we have:

22c + 33d

Multiply by 1

(22c + 33d) * 1

Express 1 as 3/3

(22c + 33d) * 3/3

Evaluate the product

(66c + 99d) * 1/3

Hence, the equivalent expressions are (a), (c) and (e)

Read more about equivalent expressions at:

brainly.com/question/27911936

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Bestie bestie bestie 2467

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